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It is proved that 3arccosx arccos (3x-4x & # 178;) = π, (- 1 / 2 ≤ x ≤ 1 / 2)
There are some problems in the proposition 4x & # 178; it's very troublesome to use derivative to prove 4x ^ 3, so it's easy to prove 3arccosx arccos (3x-4x ^ 3) = π by using elementary method, that is, to prove 3arccosx = π - arccos (3x-4x ^ 3) by taking cosine value on the left side and using triple angle formula cos3t = 4 (cost) ^ 3-3cost, cos3arccosx = 4 can be obtained
Prove the identity | X-2 | - 1 | = | x-3 | - | X-2 | + | X-1 | - 1
Ask the great God to have the full score written by QAQ
||x-2|-1|=|x-3|-|x-2|+|x-1|-1
x>=3:
|x-2-1|=x-3-(x-2)+(x-1)-1
x-3=x-3
two
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