Expressing arcsin5 / 13 + arccos (- 3 / 5) with an inverse trigonometric function value I want to ask why the final inverse triangle is expressed in COS instead of sin Is there anything particular about using sin or cos

Expressing arcsin5 / 13 + arccos (- 3 / 5) with an inverse trigonometric function value I want to ask why the final inverse triangle is expressed in COS instead of sin Is there anything particular about using sin or cos


Because what he wants to show is the angle of the second quadrant, if it is
Arcsin angle may be the first quadrant or the second quadrant