The straight line M: x-2y = 0 rotates 45 degrees counterclockwise around the point P (2,1) to obtain the straight line L, and the equation of the straight line L is obtained

The straight line M: x-2y = 0 rotates 45 degrees counterclockwise around the point P (2,1) to obtain the straight line L, and the equation of the straight line L is obtained


Let L: y = k'x + B ∵ the included angle between M and l be 45 ° Tan 45 ° = | (k '- K) / (1 + k'k) |, that is: ± 1 = (k' - 1 / 2) / (1 + K '/ 2) it is concluded that: K' = 3 or K '= - 1 / 3 ∵ the line L is obtained from m by 45 ° counterclockwise ∵ K' > k, ∵ K '= 3 and ∵ the line L passes through point P (2,1)



The abscissa of a point P on the line X-Y + 1 = 0 is 3. If the line rotates 90 ° counterclockwise around the point P to get a line L, then the equation of line L is______ .


The slope of the line L is - 1 because it passes through points (3, 4) and is perpendicular to the line X-Y + 1 = 0. The equation of the line L is y-4 = - 1 (x-3), that is, x + Y-7 = 0, so the answer is x + Y-7 = 0



The abscissa of a point P on the line 2x + y = 0 is 3. If the line rotates 90 degrees counterclockwise around the point P to get a line L, then the equation of the line ll is


Coordinates of point P: P (3, - 6)
If the line is rotated 90 degrees counterclockwise around point P, then the line L is the normal of the line
The slope of line l k = - 1 / (- 2) = 1 / 2
Let the line l be y = 1 / 2x + B and pass through the point P (3, - 6)
Then: y = 1 / 2x - 15 / 2