Draw the right triangle AOB rotated 180 degrees counterclockwise around point o

Draw the right triangle AOB rotated 180 degrees counterclockwise around point o

As shown in the figure, the triangle ABC is an equilateral triangle, and the point O is the intersection point of the triangle ABC bisector. Rotate the triangle around the point O in a counterclockwise direction, and draw the figure after rotating 30 & # 186; 60 & # 186; 90 & # 186; tell me how to do it! Thank you very much

S△ABC＝6×8×1／2＝24
Because o is the intersection of the bisectors of triangle angles
So od = OE = of
Let od be X
Then s △ ABC = (AB × of × 1 / 2) + (AC × OE × 1 / 2) + (BC × OD × 1 / 2)
＝5x+3x+4x＝24
x＝2

As shown in the figure, in the rectangular coordinate system, given the points a (- 3, 0), B (0, 4), make continuous rotation transformation for △ OAB, and get the triangles ①, ②, ③, ④ in turn Then the coordinates of the right angle vertex of the triangle are___ ．

From the original figure to figure 3, it is equivalent to translating 12 units of length to the right. If the right angle vertex is (36,0) after three times of translation, and it is still (36,0) after one time of rotation to triangle 10, then the coordinates of the right angle vertex of triangle 10 are (36,0). So the answer is: (36,0)