It is known that the circle C and the y-axis intersect at two points m (0, - 2), n (0, 2), and the center of the circle C is on the straight line 2x-y-6 = 0. (1) find the equation of the circle C; (2) make a straight line through the center of the circle C, so that the line AB sandwiched between two straight lines l1:2x-y-2 = 0 and L2: x + y + 3 = 0 is exactly bisected by the point C, and find the equation of the straight line

It is known that the circle C and the y-axis intersect at two points m (0, - 2), n (0, 2), and the center of the circle C is on the straight line 2x-y-6 = 0. (1) find the equation of the circle C; (2) make a straight line through the center of the circle C, so that the line AB sandwiched between two straight lines l1:2x-y-2 = 0 and L2: x + y + 3 = 0 is exactly bisected by the point C, and find the equation of the straight line


(1) Because the circle C and the y-axis intersect at two points m (0, - 2), n (0, 2), the ordinate of the center C is 0. Because the center C is on the straight line 2x-y-6 = 0, so x = 3. So the center C (3, 0), radius | MC | = 32 + 22 = 13. So the equation of the circle C is (x-3) 2 + y2 = 13



Given that the circle C passes through two points a (0,0), B (2,2), and the center of the circle is on the straight line y = 2X-4, the standard equation of circle C is obtained


(x+a)^2+(y+b)^2=c
Passing a (0,0) and B (2,2) by circle C
a^2+b^2=c
(2+a)^2+(2+b)^2=c
a+b+1=0
a. B is the center of the circle, so
b=2a-4
-a-1=2a-4
3a=3
a=1
b=-2
c=5
The equation is: (x + 1) ^ 2 + (Y-2) ^ 2 = 5



Find the following circular equations: (1) passing through point a (- 2,0), the center of the circle is (3, - 2) (2) the intersection of the circle C and the Y axis on the straight line 2x-y-7 = 0 and two points a (0, - 4). B (0, - 2)


(1)r^2=(3+2)^2+(-2-0)^2=29
(X-3)^2+(y+2)^2=29
(2) The vertical bisector of a (0, - 4). B (0, - 2) r: y = - 3
And because the center of the circle is on the straight line 2x-y-7 = 0, we get the center of the circle (2, - 3)
r^2=(0-2)^2+(-2+3)^2=5
(x-2)^2+(y+3)^2=5
(Note: radius = the distance from the center of the circle to a point on the circle)