If the sum of three numbers is equal to 18 and the sum of their squares is equal to 116, then the three numbers are equal______ ．

If the sum of three numbers is equal to 18 and the sum of their squares is equal to 116, then the three numbers are equal______ ．

Let the sequence be A-D, a, a + D. then we can get A-D + A + A + D = 18, and (A-D) 2 + A2 + (a + D) 2 = 116. The solution is a = 6, d = 2 & nbsp; or & nbsp; a = 6 & nbsp; d = - 2, so the three numbers are 4, 6, 8. So the answer is: 4, 6, 8

If the sum of three numbers is equal to 18 and the sum of their squares is equal to 116, then the three numbers are equal______ ．

Let the sequence be A-D, a, a + D. then we can get A-D + A + A + D = 18, and (A-D) 2 + A2 + (a + D) 2 = 116. The solution is a = 6, d = 2 & nbsp; or & nbsp; a = 6 & nbsp; d = - 2, so the three numbers are 4, 6, 8. So the answer is: 4, 6, 8

Three numbers are known to form an arithmetic sequence, their sum is equal to 18, and their sum of squares is equal to 16

Let these three numbers be a-di, a, a + di (I is an imaginary number)
(a-di)+a+(a+di)=3a=18
a=6
(6-di)²+6²+(6+di)²=16
108-2d²=16
D = root 46

If the sum of three numbers is equal to 18 and the sum of their squares is equal to 116, then the three numbers are equal______ ．

Let the sequence be A-D, a, a + D. then we can get A-D + A + A + D = 18, and (A-D) 2 + A2 + (a + D) 2 = 116. The solution is a = 6, d = 2 & nbsp; or & nbsp; a = 6 & nbsp; d = - 2, so the three numbers are 4, 6, 8. So the answer is: 4, 6, 8