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If there is a point C on the line AB with a length of 16 cm, then the distance between the midpoint of AC and BC is
Let the midpoint of AC be D and the midpoint of BC be e
Then there are:
DC=1/2AC
CE=1/2BC
AB=AC+BC
DC+CE=DE=1/2(AC+BC)=1/2AB=8CM
Given the line segment AB, C is the point on AB, AC = one third BC, D is the midpoint of BC. (1) if the line segment AB = 16cm, find the length of the line segment CD;
(2) If e is the midpoint of AD and CE = 1.5cm, find the length of ab.
AC = one third BC, ab = 16cm, so AC = 4, BC = 12, CD = 1 / 2BC = 6
E is the midpoint of AD, let AC = x, BC = 3x, ad = 2.5x, CE = 1 / 4x, ab = 4x,
5 / (1 / 4x) = AB / 4x, ab = 24cm
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