In triangle ABC, D is on AB, CD bisector angle ACB, if CB equals a, CA equals B, find CD The RT process is detailed CA doesn't equal CB. Notice

In triangle ABC, D is on AB, CD bisector angle ACB, if CB equals a, CA equals B, find CD The RT process is detailed CA doesn't equal CB. Notice

∵ CD bisection ∠ ACB
∴∠dcb=∠dca
ca=cb
All △ BCD is equal to △ ACD
∵ d three points of abd are collinear on ab
⊥ D is the midpoint of AB and CD ⊥ ab

The isosceles triangle ABC, ab = AC, vertex angle a = 20, take a point D on AB to make ad = BC, then angle BDC =?
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30

If the line AB = 10cm, there is a point C on the line AB, and BC = 4cm, and M is the midpoint of the line AC, then am=______ cm．

When point C is in the middle of AB, as shown in the figure above, AC = ab-bc = 10-4 = 6, am = 12ac = 3cm; when point C is outside AB, AC = AB + BC = 10 + 4 = 14, am = 12ac = 7cm

If the line AB = 10cm, there is a point C on the line AB, and BC = 4cm, and M is the midpoint of the line AC, then am=______ cm．

When point C is in the middle of AB, as shown in the figure above, AC = ab-bc = 10-4 = 6, am = 12ac = 3cm; when point C is outside AB, AC = AB + BC = 10 + 4 = 14, am = 12ac = 7cm

If there is a point C on the line AB such that ab: BC = 5:2, find MC

M is the midpoint of ab
AM＝10
So AB = 2am = 20cm
BM=AM=10cm
AB:BC=5:2
So BC = 20 × 2 △ 5 = 8cm
If a is between BC
Then MC = bm-bc = 2cm
If B is between AC
Then MC = BM + BC = 18cm
So MC = 2cm or 18cm