Given that the line segment AB = 15cm, the point C is on the line segment AB, BC = 23ac, and D is the midpoint of BC, the length of the line segment ad is calculated

Given that the line segment AB = 15cm, the point C is on the line segment AB, BC = 23ac, and D is the midpoint of BC, the length of the line segment ad is calculated


As shown in the figure, ∵ BC + AC = AB = 15, BC = 23ac ∵ AC = 9cm, BC = 6cm, ∵ D is the midpoint of BC, ∵ CD = 3cm, ∵ ad = AC + CD = 12cm



As shown in the figure, C is a point on line AB and D is the midpoint of line CB. Given that the sum of the lengths of all line segments in the figure is 23, and the length of line AC and line CB are both positive integers, what is the length of line AC?


Let AC = y, CD = BD = x, then AC + CD + DB + AD + AB + CB = 23, that is, y + X + X + (x + y) + (2x + y) + 2x = 23, then 7x + 3Y = 23, because the length of line AC and line CB are positive integers, so we can know that the maximum x is 3, we can know that x = 3, y is a decimal, not consistent; X = 2, y = 3, consistent with the meaning; X = 1, y is a decimal, not consistent. So AC = 3



As shown in the figure, C is the midpoint of line AB and D is the midpoint of line AC. given that the sum of the lengths of all line segments in the figure is 39, the length of line AC can be calculated


Let CD = x, then AC = BC = 2x, ad = 3x, ab = 4x, DB = X.. X + 2x + 2x + 3x + 4x + x = 39, the solution is x = 3 〈 AC = 2x = 6. Answer: the length of line AC is 6