The length, width and height of a cuboid are ACM, BCM and HCM respectively. If the height is increased by 2cm, its volume will be increased by () cubic centimeter. The formula divides 35 into the sum of two prime numbers, and there are () kinds of methods. The square building block with the volume of 37 cubic centimeter occupies () area on the table
The length, width and height of a cuboid are ACM, BCM and HCM respectively. If the height increases by 2cm, its volume increases (2Ab)
)Cubic centimeter
There are problems with the last two questions
If a copper coin is a circle with a radius of ACM and a square hole with a side length of BCM in the middle, the upper surface area of the coin is () cm
(π a squared / 4) - B squared thank you
If the width of a rectangle is ACM, and its length is 2cm more than its width, then its circumference is [] cm
The length is a + 2
So the perimeter is 2 (a + 2 + a) = 4A + 4