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A right triangle, two of which are 6cm and 8cm respectively, is rotated along the hypotenuse 10cm for one circle to get a body of revolution?
Hello, Han yingnuan, it's for you
6 × 8 △ 10 = 4.8 cm
3.14×4.8×4.8×10÷3
=241.152 cm3
Its volume is 241.152 cubic centimeters
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There is a right triangle. The lengths of the two right sides are 8cm and 6cm respectively. The length of the hypotenuse is 10cm. What is the volume of the figure formed after rotating one circle along the hypotenuse?
The volume is the base area * height. From the question, we can see that the radius of the base area is the height of the hypotenuse = 8 × 6 △ 10 = 4.8cm, while the question is made up of two cones with the same base, so we can see that h = C (hypotenuse) = 10cm
∴V=1/3*S*h=1/3×π×（4.8）^2×10≈241（cm^3）
A triangle, three sides are 8cm, 6cm, 10cm, area
∵6²﹢8²=100=10²
The triangle is a right triangle
The area of this triangle is: 6 × 8 △ 2 = 24 (# #)
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