There are 300 answers to oral arithmetic in Volume 2 of grade 5

There are 300 answers to oral arithmetic in Volume 2 of grade 5

Grade 5 Volume 2 oral arithmetic 43
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3×3×3=27dm3
1.2×1.2×1.2=1.728m3
twenty-four
two
3×3×3=27cm2
0.36×100=36m3

Fifth grade volume two mathematical oral arithmetic training answers
 

1.2/3  1/3  1/5   3/4   3/5  2/5   3/4   2/5   1/3   2/3   3/4   5/62.＞   ＝    ＜    ＜3.

Mathematical calculation problem
The square of (X-Y) multiplied by the square of (x + y)

(x-y)(x-y)(x+y)(x+y)
=(x-y)(x+y)(x-y)(x+y)
(X-Y) (x + y) = x ^ 2-y ^ 2. This is the back formula
So the original formula = (x ^ 2 + y ^ 2) ^ 2
Let x ^ 2 be a and Y ^ 2 be B,
(a-b) ^ 2 = a ^ 2-2ab + B ^ 2, which is also the back formula
Then you can substitute it to get x ^ 4-2x ^ 2Y ^ 2 + y ^ 4
It's a mental arithmetic problem

There is a fraction. If 6 is added to the denominator, the numerator remains unchanged and the original fraction is 16. If 4 is added to the numerator, the original denominator remains unchanged and the original fraction is 14___ ．

Let the molecule be X. & nbsp; & nbsp; & nbsp; 6x-6 = (x + 4) × 4 & nbsp; & nbsp; & nbsp; & nbsp; 6x-6 = 4x + 16, & nbsp; & nbsp; & nbsp; 6x-4x = 16 + 6, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2x = 22, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 11; 6 × 11-6 = 60, so the answer is: 1160

There is a fraction. If 3 is added to the denominator, the numerator will remain unchanged and the fraction will be reduced to 1 / 6. If 4 is added to the numerator, the original denominator will remain unchanged and the fraction will be reduced to 2 / 3

Let the numerator be x and the denominator be y
x/y+3=1/6 - y=6x-3 ①
x+4/y+2/3 3x+12=2y②
Substituting Formula 1 into formula 2
3x+12=12x-6
x=2
Y = 9, then the original fraction is 2 / 9

There is a fraction. If 6 is added to the denominator, the numerator remains unchanged and the original fraction is 16. If 4 is added to the numerator, the original denominator remains unchanged and the original fraction is 14___ ．

Let the molecule be X. & nbsp; & nbsp; & nbsp; 6x-6 = (x + 4) × 4 & nbsp; & nbsp; & nbsp; & nbsp; 6x-6 = 4x + 16, & nbsp; & nbsp; & nbsp; 6x-4x = 16 + 6, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2x = 22, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 11; 6 × 11-6 =

If the difference between the denominator and the numerator of the original fraction is 63, what is the original fraction

"11-4=9
63/7=9
The original fraction is: 4 * 9 = 36
The original denominator is: 11 * 9 = 99
The original score was 36 out of 99“

If the fraction is 29 out of 5 and a is added to both denominator and numerator, the ratio of denominator to numerator is 7:19, what is a

That is 29 + A: 5 + a = 19:7, the multiplication inside = 95 + 19A, the multiplication outside = 203 + 7a, that is 95 + 19A = 203 + 7a, so 12a = 108
So the solution is a = 9
More practice, the basic is that the numerator and denominator are a little poor, mental arithmetic will come out