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If the numerator of a fraction is expanded by 5 times, the denominator is reduced to 1 / 5, and then 2 / 7, the original fraction is ()
Hello, 211030352
2 and 1 / 7 = 15 / 7
The original molecule is: 15 △ 3 = 5
The original denominator is: 7 △ 1 / 5 = 35
The original score is: 5 / 35 = 5 / 35
The numerator of a fraction is expanded to five times of the original one, and the denominator is reduced to one third of the original one, so as to get 7 and 1 / 2?
7 and 1 / 2 = 15 / 2
Original score
=15 / 2 / 5 / 3
=1 / 2
The sum of numerator and denominator of a fraction is 92. If 16 is subtracted from numerator and denominator at the same time, the ratio of numerator and denominator is 1:3, so the fraction is 92______ ．
The present numerator: (92-16 × 2) × 11 + 3, = 60 × 14, = 15, the present denominator: (92-16 × 2) × 31 + 3, = 60 × 34, = 45, the original numerator: 15 + 16 = 31, the original denominator: 45 + 16 = 61, a: the original fraction is 3161
The sum of the numerator and denominator of the fraction is 92, and the numerator and denominator are subtracted by 16 to get a new fraction of 1 / 3. What is the original fraction?
(92-16 × 2) / (1 + 3) + 16 = 31 molecules
(92-16 × 2) / (1 + 3) × 3 + 16 = 61 denominator
The original score was 31 / 61
The numerator of 1993 / 1992 subtracts a number. After adding this number to the denominator, the fractional value is two-thirds. Find this number
Set to X
(1992 - X) / (1993 + X) = 2/3
Namely
2(1993 + X) = 3(1992 - X)
Namely
5X = 3*1992 - 2*1993
Solution
X = 398
The number is 398
1992 / 1993 numerator minus a number, denominator plus this number, the fractional value is 2 / 3, find this number
(1992x3-1993x2)/(2+3)=398
A fraction is 8 out of 15. The denominator of the original fraction is 35 larger than the numerator. What's the original fraction
In about 8 / 15, the denominator is 7 times larger than the numerator,
If the denominator of the original fraction is 35 larger than the numerator, then the denominator and numerator are all 5 (because 35 / 7 = 5), that is 40 / 75
Add both the numerator and denominator of 113______ It can be divided into 13
Let X be added to the numerator and denominator of 113 at the same time, which can be reduced to 13. From this, we can get the following equation: & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 1 + x13 + x = 13, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 13 + x = 3 (1 + x), & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 13 + x = 3 + 3x, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 5. & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; so the answer is: 5
How much of the numerator and denominator of 3 / 13 can be added at the same time to divide it into 1 / 3 (process)
(1*5)/(3*5)=5/15
5-3=2
15-13=2
So the numerator and denominator of 3 / 13 can be divided into 1 / 3 by adding 2 at the same time
The denominator of a number is 13 larger than the numerator, and the numerator can be divided into 2 / 9 after subtracting 1
When the numerator is reduced by 1, the denominator of the original fraction is 13 + 1 = 14 larger than that of the numerator
14/（9-2）=14/7=2
That is to say, if the numerator of the original fraction is reduced by 1 and the denominator is reduced by 2 times at the same time to get the present fraction of 2 / 9, then it will be zero before 1
（2*2）/（9*2）=4/18
So the original score is (4 + 1) / 18 = 5 / 18
A: slightly
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