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How many 3-digit odd numbers without repetition can be made up of 10 numbers 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 Excuse me, I've read it. The answer is 8 × 8 × 5 = 320 But I don't understand why. Can someone help me
Since it's an odd number, it means that the one digit number is 1 357 9, so because it's not repeated, Baiwei and ten digits can't be used, but the hundred digits can't start from 0, so it's 8. Ten digits can have 0, so it's 8. The one digit number is 1 357 9, so it's 5
Use the ten numbers 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 to form even numbers without repetition. Thank you for your details
There are two cases: (1) if the digit is 0, there are nine choices for the hundred (any one from 1 to 9); if the digit is 10, there are eight choices (except 0 and the digit), there are a total of 8 * 9 = 72 cases. (2) if the digit is not 0, there are four choices (2468). If the digit is not 0, there are eight choices (except 0 and the digit), there are eight choices (...)
A multiplication formula of two digits multiplied by two digits. One of the multipliers is 29. If you add two multipliers and the product, you will get 839. What's the other multiplier
From the multiplication formula, we can know that the product of 29 and a number is 29 times of this number. Add this product to 29 and another multiplier, that is, the sum of (29 + 1) times of that multiplier and 29. In other words, subtracting the difference of 29 from 839 is (29 + 1) times of the other multiplier. Therefore, the other multiplier is (839-29)? 9 + 1) = 27
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