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Fill the four numbers 5.6.7.8 in the following formula to make the sum on the left the largest and the sum on the right the smallest The four numbers 5.6.7.8 are filled in the following formula respectively to make the sum on the left the largest and the sum on the right the smallest （ ）（ ） （ ）（ ） + （ ）（ ） +（ ）（ ） ———————————— ———————————— （ ）（ ） （ ）（ ）
Left 86 + 75 = 161
Right 57 + 68 = 125
Four 2's and one 1's, plus, minus, multiply, divide, brackets. (each can only be used once), form an equation equal to 7
2*(2-2/2)+1=7
2×（2-2÷2）+1
Big brother, first calculate multiplication and division, then add and subtract!
Primary school teacher taught. You won't forget it!
Add operational symbols or brackets between the numbers below to make the equation true______ 2______ 3=11______ 2______ 3______ 4=11______ 2______ 3______ 4______ 5=1．
(1) (1 + 2) △ 3, = 3 △ 3, = 1; (2) 1 × 2 + 3-4, = 2 + 3-4, = 1; (3) [(1 + 2) × 3-4] / 5, = [9-4] / 5, = 1; so the answer is: (+), /; ×, +, -; [(+), ×,], /
1 3 4 6 = 24 (fill in the space with addition, subtraction, multiplication, division and brackets to make the formula equal to 24)
1. There is a unique solution to the operation of addition, subtraction, multiplication and division: 6 (1-3) 4 = 24
2. If the power is added, the solution is as follows:
1^3×4×6=24
1^3×6×4=24
(1^4+3)×6=24
(3+1^4)×6=24
4×1^3×6=24
4÷1^3×6=24
4÷(1^3÷6)=24
4^(1^3)×6=24
4×6×1^3=24
4×6÷1^3=24
4×6^(1^3)=24
6×1^3×4=24
6÷(1-3÷4)=24
6÷1^3×4=24
6÷(1^3÷4)=24
6^(1^3)×4=24
6×(1^4+3)=24
6×(3+1^4)=24
6×4×1^3=24
6×4÷1^3=24
6×4^(1^3)=24
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