There are +. -. × in the number composition square of 123456789 [each number cannot be repeated] □－□＝□ × □ ÷ □＝□ ＝ □＋□＝□

There are +. -. × in the number composition square of 123456789 [each number cannot be repeated] □－□＝□ × □ ÷ □＝□ ＝ □＋□＝□

9-5=4
6÷3=2
7+1=8

Put the nine numbers 1 ~ 9 into the square so that the sum of the three numbers in each horizontal, vertical and oblique line is equal (each number can only be used once)

8 3 4
1 5 9
6 7 2

Can you fill in the following boxes with numbers 1-9? (numbers can't be repeated) () + () = () + () = () + () = ())

It's impossible
Let a, B, C, D, e, F, G, h, I be nine numbers from 1 to 9, and a + B = C, D + e = f, G + H = I, then
C + F + I = (1 + 2 + 3 +... + 9) / 2 = 22.5, but C, F and I are all integers

Fill the 9 numbers 1, 2, 3, 4, 5, 6, 7, 8 and 9 in brackets to form 3 groups of numbers, which cannot be repeated!
（）+（）=（）
（）-（）=（）
（）*（）=（）

（4）+（5）=（9）
（8）-（1）=（7）
（2）*（3）=（6）

() + () = () + () () () how many different ways are there to fill in the nine numbers from 1 to 9 in the brackets above?

In 0-9, there are 2 + 3 = 1 + 4, 2 + 4 = 1 + 5, 2 + 5 = 1 + 6 = 3 + 4, 2 + 6 = 1 + 7 = 3 + 5, 2 + 8 = 1 + 9, 0 + 3 = 1 + 2, 0 + 5 = 2 + 3, 0 + 7 = 3 + 4, 0 + 9 = 4 + 5. The rest is: 100 * a + 10 * (B + C) = 10 (D + e), where a can only be 1, The BCDE can be replaced by the above formula. Since a = 1, it is unnecessary to consider the one with the addend 1

From the nine numbers (1 ~ 9), each number can only be used once. Select six numbers and fill in the brackets to form three equal fractions
( ) ( ) ( )
------- = ------- = --------
( ) ( ) ( )

1/2=3/6=4/8
1/2=4/8=3/6
2/1=6/3=8/4
2/1=8/4=6/3
3/6=1/2=4/8
3/6=4/8=1/2
4/8=1/2=3/6
4/8=3/6=1/2
6/3=2/1=8/4
6/3=8/4=2/1
8/4=2/1=6/3
8/4=6/3=2/1

Please put the nine numbers from 1 to 9 in brackets (9 and 6 have been filled in)
()*()-()=(9)(6)/()()+()=()

(1)*(7)-(2)=(9)(6)/(4)(8)+(3)=(5)

Put the nine numbers from 1 to 9 in brackets (9 and 6 have been filled in)
() multiply () - () = 96 divided by () + () = ()

2*5-7=96/48+1=3

Fill in 1, 2, 3, 6, 7, 8 and 9 in □, so that the formula holds: □ + □ = □ - □ = □

According to the meaning of the question, the original formula can be written as: ABCDE, then the formula is: a + B = 2c-d = 1E; the remaining numbers are: 3, 6, 7, 8, 9. Discuss the value of E: ① if e = 3, then 1E is 13, because 6 + 7 = 13, so a and B are 6 and 7 respectively, the remaining 8 and 9, no matter how to combine 2c-d is not equal to 13, do not meet the requirements; ② if e = 3, then 1E is 13, because 6 + 7 = 13, so a and B are 6 and 7 respectively If e = 6, then 1E = 16, 7 + 9 = 16, so a and B are 7 and 9 respectively, and there are 3 and 8 left, no matter how combined, 2c-d is not equal to 16, which does not meet the requirements; ③ e = 7, then 17 = 17, 8 + 9 = 17, so a and B are 8 and 9 respectively, and there are 3 and 6 left, 23-6 = 17, which meets the requirements; ④ e = 8, or 9, then 1E = 18 or 19, and the sum of no two numbers is 18 and 19, which does not meet the requirements; so the answer is: 8 + 9 = 23-6 = 17

9.8.6.5
How to calculate

6×[5－（9－8）]＝24