The object starts to move in a straight line at a speed of 15 meters per second, and the acceleration is 2 meters per second. What is the speed after six seconds? What is the displacement in six seconds?

First of all, we need to calculate whether the velocity of the object has decreased to 0 in six seconds, and use 0-15 = - 2T (t is the time taken for the object to reduce to 0). The solution is t = 7.5S. Because the velocity of the object has not decreased to 0 in six seconds, we can use v-15 = - 2 * 6, then the velocity after six seconds is 3m / s, and the displacement can be solved by S = 15 * 6 + (1 / 2) (- 2) 6 ^ 2 to get s = 54m. There is another formula, namely 3 ^ 2-15 ^ 2 = 2 * (- 2) s, s = 54m

The initial velocity of the object is 12 meters per second, and the acceleration is 2 meters per second. The displacement of the object in a certain second is 6 meters. How far can it move after that

First of all, what is a certain second
S = vt-1 / 2at square
6=V-1/2*2*1
V=7
It shows that this one second is a second with an initial speed of 7 and a final speed of 5 after one second
How far can he move when the speed is 5
A = 2, initial speed is 5, after 2.5 seconds, speed is 0, stop
S = vt-1 / 2at square
S = 5 * 2.5-1 / 2 * 2 * 2.5 square = 6.25

An object moves uniformly in a straight line with an acceleration of 2 meters per second, and the displacement in the second is 12 meters
9 meters per second, 17 meters per second

Let me tell you with a simple algorithm: use 12m / 1s = 12m / s, which is the average speed in the second second second, so it is also the instantaneous speed of 1.5s. Then, according to v = V0 + at, we can get V0 = 9m / s. if we answer your question,

Point P is a point outside the trapezoidal ABCD plane. PA is vertical to ABCD, AB is parallel to CD, AB is vertical to ad, and E is the midpoint of PC. can EBD be vertical to ABCD

The plane EBD is not perpendicular to ABCD
Connect AC, in the triangle APC, e is the midpoint of PC, then make ef perpendicular to AC through point E, then point F is the midpoint of AC, because ABCD is trapezoid, so point F is not on BD

In the pyramid s-abcd, the bottom surface ABCD is square, the side edge SD ⊥ and the bottom surface ABCD, E.F. are the midpoint of AB and SC respectively

It is proved that: in plane SDC, FG is parallel to CD, intersecting SD with point G, connecting Ag; through F, the high FH on the side CD of triangle CDs, the perpendicular foot is h, and connecting EH. Because FG is parallel to CD, and CD is parallel to AE (known + square property), FG is parallel to AE, and because F, e are the middle point, so f

As shown in the figure, it is known that s is a point out of the plane of the parallelogram ABCD, m and N are points on SA and BD respectively, and SMMA = bnnd. Then the line Mn______ Plane SBC

It is proved that bnnd = bgag can be obtained by making ng ‖ ad through N, intersecting AB with G and connecting mg. According to the known condition bnnd = SMMA, SMMA = bgag, ⊄ mg ‖ sb. ⊄ mg ⊄ plane SBC, sb ⊂ plane SBC, ⊂ mg ‖ plane SBC. Ad ‖ BC, ⊄ ng ‖ BC, ng ⊄ plane SBC, BC ⊂ plane SBC ⊂ ng ‖ plane SBC

As shown in the figure, it is known that s is a point out of the plane of the parallelogram ABCD, m and N are points on SA and BD respectively, and SMMA = bnnd. Then the line Mn______ Plane SBC

In the following four equations, ABCD represents a number. A equals B plus 3, C equals a plus a, D equals a plus C plus 7, D equals B plus 40?
How much is each

A=B+3
C=A+A=2(B+3)=2B+6
D=A+C+7=B+3+2B+6+7=3B+16
3B+16=B+40
2B=24
B=12
A=12+3=15
C=15+15=30
D=12+40=52

A + B + C = 61, a + C + D = 71, a + B + D = 62, B + C + D = 64, what are the values of ABCD?

A+B+C=61 -------1
A+C+D=71 -------2
A+B+D=62 -------3
B+C+D=64 -------4
By adding the four formulas, we can get the following results:
3(A+B+C+D)=61+71+62+64=258
A+B+C+D=86------------5
Equation 5-1, we get
D=86-61=25
B=86-71=15
C=86-62=24
A=86-64=22

Given that a + B is equal to 0, B + C is equal to 0, C + D is equal to 0, D + F is equal to 0, which of the four numbers of ABCD are opposite to each other and which are equal?

A and BD, B and C, C and D are opposite numbers, a and C, B and D are equal

The object starts to move in a straight line at a speed of 15 meters per second, and the acceleration is 2 meters per second. What is the speed after six seconds? What is the displacement in six seconds?