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Physical S-T, V-T image, how to judge the acceleration or deceleration, the direction of acceleration?
s-t
If the slope is flat, the wood moves (or moves in a circle)
v-t
Is it above or below the x-axis
Direction of acceleration
Acceleration is the same as V direction
Deceleration is opposite to V direction
Is there any acceleration unit other than meter per second?
The power of M times s
The relationship between the displacement of a particle and time is: S = 4T + 2 times the square of T, the units of S and T are meter and second respectively
For S = 4T + 2T ^ 2 = v0t + 1 / 2at ^ 2
v0=4m/s a=4m/s^2
The relation between the displacement of a particle and time is s = 4T + 2T ^ 2. The unit resolution of S and t is m and s
The initial velocity is 4m / s,
Acceleration 4m / S ^ 2
Question: how to find the side area of prism
The side area of straight prism is: perimeter of bottom * height. The side area of oblique prism is: perimeter of straight section * edge length, or: s side = n * a * b * SiNx (n is the number of sides, a and B are both sides of bottom, X is the angle between a and b)
How to find the formula of base area of regular 6 prism?
How to find the length of regular triangular prism?
3 root 3 / 2 × edge length
Regular hexagonal prism and other prism base area calculation method (formula is OK), as detailed as possible, thank you
To find the area of the base of a regular hexagon and other prisms is to find the area of a regular hexagon and other regular n-sided forms. The formula for the area of a regular n-sided form is s = (a ^ 2 * n * cot (PI / N)) / 4, where n is the number of sides and a is the length of the side with multiple deformations
How to deduce the formula of base area of regular hexagonal prism?
(3 √ 3 / 2) a & # 178; that's it. To be more specific, I'm going to bed
It's a combination of six regular triangles. The area of a triangle is: 1 / 2 × a × a × sin60 = √ 3 / 4 × a ^ 2, then multiply by 6
Full area formula of prism
Bottom area + side area
The area formula of quadrangular prism
Ground area * height, ground = length * width, so the formula is length * width * height
RELATED INFORMATIONS
- 1. The relationship between the displacement of a particle and time is x = 4T + 2t2. If the units of X and T are m and s respectively, the initial velocity and acceleration of the particle are () A. 4m / s and 4m / S2B. 0 and 4m / S2C. 4m / s and 2m / S2D. 4m / s and 0
- 2. 5. The relation between the displacement of a particle and time is: S = 4t-2t2. The units of S and T are m and s respectively,
- 3. The relationship between the displacement of a particle moving in a straight line and time is x = 4t-2x ^ 2. The units of X and T are m and s respectively
- 4. The object starts to move in a straight line at a speed of 15 meters per second, and the acceleration is 2 meters per second. What is the speed after six seconds? What is the displacement in six seconds?
- 5. When the object moves in a straight line with uniform deceleration, the initial velocity is 3 M / s, the acceleration is the second power of - 0.4 m / s, and the displacement of the object passing through in a certain second is 0.4 M, How long has the object been moving before this second? Please write down the specific answer process
- 6. The speed of a train at the end of the fourth second can be calculated by making a uniformly accelerated linear motion with the initial speed of 2 meters per second and the square acceleration of 0 and 5 meters per second And the average speed of the train in the first four seconds
- 7. What is the displacement ratio with equal time interval in uniform acceleration linear motion I remember that the ratio of displacement in the same time interval is 1:3:5:7, but it's not very clear,
- 8. Why is the average acceleration equal to the instantaneous acceleration in the uniform linear motion
- 9. A vertical projectile moves in a straight line with constant velocity in both ascending and descending stages, and its acceleration is equal to that of a free falling body The initial velocity of the straight upward motion is 30 meters per second. After 2 seconds, 3 seconds and 4 seconds, what is the displacement of the object? What is the distance? What is the velocity at the end of each second?
- 10. When an object starts to move in a straight line with constant acceleration of A1, when it is in motion An object starts to move at a constant acceleration with an acceleration of A1. The motion time is T1. Number of Views: 825 reward points: 20 | solution time: 2009-10-31 00:21 | questioner: qiuri123 When an object starts to do uniform acceleration motion with acceleration A1 from rest, changes to uniform deceleration linear motion with acceleration A2 after time T1, and stops after time T2, the average velocity of the object in all time is () A.a1t1/2 B a1(t1+t2)/2 C a1ti(t1-t2)/2(t1+t2) D a2t2/2 Why is a1t1 = a2t2
- 11. How to get s = v0t + 1 / 2at square
- 12. Is the displacement difference formula the expression of displacement x = v0t-1 / 2at ^ 2?
- 13. What's the difference between the two formulas of compulsory physics: x = v0t + 1 / 2at ^ and x = (VO + VT) / 2 × t?
- 14. In the formula s = VT + 1 / 2at & # 178; s, t (t is not equal to 0), find the expression of V In the formula s = 6.28r (R + H), we know s = 628, r = 5, and find H
- 15. The area formula of triangle formed by linear function y = KX + B and coordinate axis I want to summarize the reasoning process and formula
- 16. The area of the triangle formed by the line passing through point a (2, - 3) and the coordinate axis is 4
- 17. The equation of circle: given the points P1 (4,9), P2 (6,3), circle C is a circle with the diameter of line p1p2, then the equation of circle C is the same Please write down the detailed process, thank you
- 18. Given the slope of the straight line k = 2, P1 (3,5) P2 (x2,7) P3 (- 1, Y3) is the three points on the straight line to find x2 and Y3
- 19. 1. It is known that the line L1 is perpendicular to the line L2: 3x-4y-7 = 0, and the circumference of the triangle formed by L1 and the two coordinate axes is 10. The equation for finding L1 is 2. It is known that the fixed point a (a, 0) is on the straight line x = B (0)
- 20. As shown in the figure, if the side edge length of the triangular prism is 2, the bottom surface is an equilateral triangle with side length of 1, Aa1 ⊥ surface a1b1c1, and the front view is a rectangle with length of 2 and width of 1, the area of the side view (or left view) of the triangular prism is () A. 3B. 23C. 1D. 32