Given that the function y = (2a + 1) x - (3-B) is a positive proportional function, the value range of a and B is obtained

Given that the function y = (2a + 1) x - (3-B) is a positive proportional function, the value range of a and B is obtained

Because y = (2a + 1) x - (3-B) is a positive proportional function,
So 2A + 1 ≠ 0
3-b=0
The solution is a ≠ - 1 / 2
b=3
Answer: a ≠ - 1 / 2
b=3

Given that the image of positive scale function y = (1-2m) x passes through the second and fourth quadrants, the value range of M is ()
A. m＞12B. m＜12C. m＜0D. m＞0

∵ the image of positive scale function y = (1-2m) x passes through the second and fourth quadrants, ∵ 1-2m < 0, ∵ m > 12

(1) If y = (3K-1) x + k-1, y decreases with the increase of X, then the value range of K is

When 3K-1 ＜ 0, the condition is satisfied, and the range is k ＜ 1 / 3

If the value of the independent variable increases by one, then the value of the function decreases by four, then k =

The answer is k = - 4

If there is no intersection between the inverse scale function y = (K + 1) / X and the positive scale function y = 2x, then the value range of K is --

K is less than - 1. There is no intersection point between the inverse function and the positive function, that is, (K + 1) / x = 2x has no solution. Multiply the left and right sides of the equation by X to get 2x-k-1 = 0, so that it has no solution, that is, b-4ac is less than 0, that is, 0-4 (- 2k-2) is less than 0, and the solution is k less than - 1

Give you a positive proportion function and an inverse proportion function, and give the image to find the value range of X when the value of inverse proportion function is greater than that of positive proportion function

There are two ways to solve this kind of problem: first, the positive proportion function and the inverse proportion function are combined into a system of binary equations (or inequalities), and the system of equations (or inequalities) is solved. Second, the problem is solved according to the image. Look at the image, and see where the positive proportion function and the inverse proportion function intersect. Then, when the image of the inverse proportion function is on the positive proportion image, it is

If the function y = (6 + 3M) x + 4n-4 is a linear function, then M and n should satisfy () and if it is a positive proportional function, then M and n should satisfy ()
Mathematics in grade two

If y = (6 + 3M) x + 4n-4 is a linear function, then the condition that m and n should satisfy is (m ≠ - 2),
If it is a positive proportional function, then M and n should satisfy (m ≠ - 2, n = 1)

If the image of positive scale function y = (3m + 1) x passes through (1. - 2), then M =?

LZ is not good at math
Take the point parameter into the function to get the result
-2=（3M+1）*1
By solving this equation, we can get m = - 1

Inverse proportion function in grade two
Points a (3,4) and B (6,2) are all on the image with inverse scale function y = 12 / X. connect ab. if M is a point on X axis and N is a point on Y axis, the quadrilateral with vertices a, B, m and N is a parallelogram, try to find the function expression of line Mn
Don't use the slope method, use the method that junior two students can understand
Need specific process

There are two cases, the graphics are not easy to draw, you draw according to what I said
The first case: point n and point m are on the positive half axis of the two coordinate axes
(1) Because AB / / nm, that is, point n is obtained by the translation of point a, point m is obtained by the translation of point B, and the direction of movement is the same as the unit. Because point n is on the Y axis, the abscissa of point n is 0, which is obtained by the translation of abscissa 3 of point a to the left by 3 units, so point B also moves to the left by 3 units, which is the abscissa of point m is 3; and the abscissa of point m is 0, This is obtained by moving point B down two units, so point a should also move down two units to get 2. This is the ordinate of point n is 2, so the coordinate of point n is (0,2), and the coordinate of point m is (3,0). At this time, the linear expression of Mn is set as y = KX + B, and y = - 2 / 3x + 2 can be obtained by substituting the coordinate of point Mn
The second case: point n and point m are on the negative half axis of the two coordinate axes
(2) In the same way, we can get that point m is obtained by the translation of point a, and point n is obtained by the translation of point B, so the expression of point m is (- 3,0), point n is (0, - 2) line Mn is y = - 2 / 3x-2

As shown in the figure, the hyperbola y = KX (k > 0) passes through the midpoint e of the edge BC of the rectangular oabc and intersects AB at the point D. if the area of the trapezoidal ODBC is 3, the analytical expression of the hyperbola is ()
A. y＝1xB. y＝2xC. y＝3xD. y＝6x

∵ hyperbola y = KX (K ＞ 0) passes through the midpoint e of the edge BC of the rectangular oabc, ∵ s △ oad = s △ OEC = 14s, rectangular oabc = 13s, trapezoidal ODBC = 1, ∵ k = 2, then the analytic formula of hyperbola is y = 2x