The known function is y = (M2-4) x ^ (4 + n) + (m-2), when m=_____ And n=_____ It is a positive proportional function when the value is zero Did the teacher make a mistake

The known function is y = (M2-4) x ^ (4 + n) + (m-2), when m=_____ And n=_____ It is a positive proportional function when the value is zero Did the teacher make a mistake

Yes, the teacher made a mistake, m-2 = 0. M = 2, but m ^ 2-4 is also equal to 0, so this function cannot be a positive proportion function

If the function: y = (3-m) x ^ (m2-9) is a positive proportional function, then M =?
Who will help me? Be right,

Because of the positive proportion, the number of times must be 1, so m2-9 = 1 leads to M = 3 or - 3, but at the same time, the coefficient of X cannot be 0, so m = 3 does not conform

It is known that the function y = (m-2) x ^ m2-3 is the quadrant of positive proportion function

According to the meaning of the title:
M^2-3=1,M-2≠0
The solution is m = - 2,
Y=-2X
A straight line passes through two or four quadrants

Given that y + m is in positive proportion to x + n (m, n is a constant), what function is y and X? If x = 3, y = 5; if x = 5, y = 11, find the functional relationship between Y and X

1. Let y + M = K (x + n), then y = KX + kn-m
2. From the above question y and X are linear function, let y = KX + B
Then 5 = 3K + B, 11 = 5K + B, k = 3, B = - 4
So y = 3x-4
Hope to help you

It is known that y + m is positively proportional to x + n (m, n is a constant);
If x = 3, y = 5; X = 5, y = 11, find out the functional relationship between Y and X

1. Let y + M = K (x + n), then y = KX + kn-m
2. From the above question y and X are linear function, let y = KX + B
Then 5 = 3K + B, 11 = 5K + B, k = 3, B = - 4
So y = 3x-4

It is known that y + m is proportional to x-n (m, n is a constant). (1) if y = - 15, x = - 1; if x = 7, y = 1, find the function relation

y+m=k(x-n)
m-15=-k(n+1) (1)
1+m=k(7-n) (2)
(2) - (1) get
16=7k-nk+kn+k
16=8k
k=2
So y + M = 2 (x-n)

It is known that y + m is in positive proportion to x-n (where m and N are constants), and it is proved that y is a linear function of X

If y + M = K (x-n)
y=kx-kn-m
y=kx-(kn+m)
K and kn + m are constants
So y is a function of degree X

If y + m is in positive proportion to x + N, m and N are constants, when x = 1, y = 2; when x = - 1, y = 1, try to find the analytic function of Y with respect to X

∵ y + m is proportional to x + N, let y + M = K (x + n), (K ≠ 0), ∵ y = KX + kn-m, ∵ y is a linear function of X, let y = KX + B, ∵ when x = 1, y = 2; when x = - 1, y = 1, ∵ 2 = K + B1 = − K + B, the solution of k = 12b = 32 ∵ y is y = 12x + 32

Given that y + A is positively proportional to x + B (a, B are constants), is y a linear function of X

Y is a linear function of X
Let y + a = K (x + b),
Then y = KX + (kb-a), so y is a linear function of X
When kb-a = 0, i.e. k = A / B, y is a positive proportional function of X

It is known that y + A is proportional to Z + a (a is a constant) and is a positive proportional function of X. x is used to express y

(y+a)/(z+a)=kx
y+a=(z+a)kx
y=(z+a)kx-a