K = cos53 / sin53.. how many degrees is the inclination angle? A direction vector of a straight line is u = (sin53, cos53). What's the inclination angle of the straight line? Can I consider it this way?

K = cos53 / sin53.. how many degrees is the inclination angle? A direction vector of a straight line is u = (sin53, cos53). What's the inclination angle of the straight line? Can I consider it this way?

k=cos53/sin53=cot53=tan(90-53)=tan37
So the inclination of the line is 37 degrees

When an object is thrown horizontally, its displacement is 25m, and the angle between it and the horizontal direction is 53 ° g, taking 10m / S2. Find: (COS 53 ° = 0.6; sin 53 ° = 0.8) (1) movement time of the object: (2) initial velocity of the object; (3) velocity of the object when it lands

(1) The horizontal displacement of the object is: x = scos53 ° = 25 × 0.6m = 15m, the vertical height is: y = ssin53 ° = 25 × 0.8m = 20m, the initial velocity of the object is: ν 0 = XT = 152m / S = 7.5m/s (2) the vertical velocity of the object is: ν y = GT = 10 × 2m / S = 20m / s, then the velocity of the object is: V 20 + V 2Y = 7.52 + 202m / S = 21.36m/s Answer: (1) the movement time of the object is 2S; (2) the initial velocity of the object is 7.5m/s; (3) the velocity of the object when it lands is 21.36m

Cos53 degrees is about a lot

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