Known set M = {X5} n = {x | (x-3a) (x + 2a) | Math enthusiast | Mathematical art

Known set M = {X5} n = {x | (x-3a) (x + 2a)

A = 0 holds
a> 0, X belongs to (- 2A, 3a)
-2a>=-3
3a

[(2m + n) ^ 2 + (2m + n) (2m-n)] / 2m, where M = 3, n = 1 / 2, simplify the evaluation!

Original formula = [4m ^ 2 + 4Mn + n ^ 2 + 4m ^ 2-N ^ 2] / (2m)
=(8m^2+4mn)/(2m)
=4m+2n
=4*3+2/2=13 .

On the inequality system X & lt; 2 of X, the solution set of X & lt; - M is x < 2, then the value range of M is

Hello, this inequality can be explained like this (the same big takes the big, the same small takes the small), then - M > = 2 gets M

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