If cos 31 ° is known to be m, then sin 239 ° Tan 149 ° is given=______ (expressed by an equation with m)

If cos 31 ° is known to be m, then sin 239 ° Tan 149 ° is given=______ (expressed by an equation with m)

∵ cos31 ° = m, ∵ sin31 ° = 1 − cos231 ° = 1 − m2, sin239 ° = sin (270 ° - 31 °) = - cos31 °, tan149 ° = Tan (180 ° - 31 °) = - tan31 °, then sin239 ° tan149 ° = (- cos31 °) · (- tan31 °) = cos31 ° tan31 ° = sin31 ° = 1 − m2

If cos 31 ° is known to be m, then sin 239 ° Tan 149 ° is given=______ (expressed by an equation with m)

∵ cos31 ° = m, ∵ sin31 ° = 1 − cos231 ° = 1 − m2, sin239 ° = sin (270 ° - 31 °) = - cos31 °, tan149 ° = Tan (180 ° - 31 °) = - tan31 °, then sin239 ° tan149 ° = (- cos31 °) · (- tan31 °) = cos31 ° tan31 ° = sin31 ° = 1 − m2

Is the tangent angle equal to?

Tangent angle?
In a triangle, there are only sharp, straight and obtuse angles
Of course, in a circle, there are plane, circumference, circumference, central angle and so on
But there is no tangent!
If we say the tangent of the angle
be
Tangent = sine / cosine
That is to say:
tanx=sinx/cosx