Let a = 1 + tan10 / 1-tan10, B = tan10 + tan50 + √ 3tan10 * tan50, Find the size relation of a, B, a + B / 2, Is (a + b) / 2

Let a = 1 + tan10 / 1-tan10, B = tan10 + tan50 + √ 3tan10 * tan50, Find the size relation of a, B, a + B / 2, Is (a + b) / 2


A = tan45 + tan10 / 1-tan10tan45 = tan55, B = tan60 (1-tan10tan50) + √ 3tan10 * tan50 = tan60, a ^ 2 + B ^ 2 / 2 > = a * b = tan55 * tan60 > tan45 * tan60 = tan60, so the relationship between them is a



What is Tan 3 π / 4


tan3π/4=tan(π-π/4)=-tan(π/4)=-1



What does tan3 α equal


tan3α=tan(α+2α)=(tanα+tan2α)/(1-tanαtan2α)=(tanα+2tanα/(1-tanαtanα))/(1-tanα2tanα/(1-tanαtanα)