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Solve the equation x ^ 2 + X + 6 = 0 in the range of complex number. Thank you for your help
△=1²-4×1×6=1-24=-23=23i²
Ψ x = (- 1 ± 23i) / 2
Ψ X1 = (- 1 + root 23i) / 2 x2 = (- 1-root 23i) / 2
Is the square of complex number (- I) 1 or - 1
What is the power of (- 1) in 2012?
It's - 1
Because (- I) ^ 2 = (- 1) ^ 2 × (I) ^ 2 = - 1
——————————- (answer questions)——————————
obviously
(-1)^2012=1
The even power of (- 1) is positive and the odd power is negative
Square of complex number (3-I / 1 + I) =?
=I know what it is
Simplification in brackets: denominator numerator multiplied by 1-I
1-2i
(1-2i)²=-3 -4i
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