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Simple calculation of sum from 41-80
（41+80）*20=121*20=2420
80x+25=100X
Come on, it's going to be a day,
100x-80x=25
20x=25
x=25/20
x=5/4
37x (1 / 80 + 1 / 43) - 43x (1 / 37-1 / 80) + 80x (1 / 37-1 / 43) is calculated by a simple method,
"X" is the multiply sign and "/" is the fractional line. I hope the kind-hearted netizens can help me to answer this question. I'm running out of time
37x(1/80＋1/43)－43x(1/37－1/80)＋80x(1/37－1/43)=37x1/80＋37x1/43－43x1/37＋43x1/80＋80x1/37－80x1/43=37/80＋37/43－43/37＋43/80＋80/37－80/43=[37/80＋43/80]＋[37/43－80/43]＋[80/37－43/37]=80/80-43/...
100X=80(X+2)
100X=80(X+2)
100X=80X+160
100X-80X=160
20X=160
X=160/20
X=8
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