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Given: - x + 3Y = 5, find the value of 5 (x-3y) square-8 (x-3y) - 5
125+40-5=160
Given - 1 + 3Y = 5, find the value of 5 (x-3y) ^ - 8 (x-3y) - 5
∵-x+3y=5, ∴x-3y=-5,
∴5（x-3y） 2 -8（x-3y）-5
=5×（-5） 2 -8×（-5）-5 =125+40-5 =160
Is x + y an integral? Why? Given - x = 3Y = 5, what is the value of 5 (x-3y) &# - 8 (x-3y) - 5? Explain
Yes, according to the definition of an integral: an integral is a part of a rational expression. In a rational expression, it can include four operations: addition, subtraction, multiplication and division. But in an integral, the divisor cannot contain letters. Monomials and polynomials are collectively referred to as integers
-X = 3Y = 5, so x = - 5 3Y = 5
Substituting 5 (x-3y) & # 178; - 8 (x-3y) - 5 = 5 (- 5-5) ^ 2-8 (- 5-5) = 580
Please check the question. My answer is different from the one above, because he gave me a different answer
-X = 3Y = 5 as - x + 3Y = 5)
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