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Given x-2y / 3y-x = 2 / 3, then the value of Y / X is
(x-2y) / (3y-x) = 2 / 3
3(x-2y) = 2(3y-x)
3x - 6y = 6y - 2x
5x = 12Y, which was substituted into the original equation and passed the test,
So y / x = 5 / 12
(x+2y)(x-2y)-3y(x-2y)
Which is it?
(x+2y)(x-2y)-3y(x-2y)
=(x-2y)(x+2y-3y)
=(x-2y)(x-y)
X + y + Z 2,4x + 2Y + Z 2,6
X + y + Z 2,4x + 2Y + Z 2,6
Subtract, get
3x+y=4
x=1,y=1
z=2-1-1=0
X = 0, y = 4, Z & lt; 0 are incompatible
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