If set a = {x | x square + 3x-4

If set a = {x | x square + 3x-4

x²+3x-4=(x+4)(x-1)

Given the set a = {x | X & sup2; - 5x + 6 = 0}, B = {x | X & sup2; + 2x-8 = 0}, C = {x | X & sup2; - 3x-4 = 0}. Finding the intersection of B and C, a (B and C)

x²-5x+6=0
（x-2）(x-3)=0
The solution is a = {2,3}
x²+2x-8=0
(x-2)(x+4)=0
The solution is b = {- 4,2}
x²-3x-4=0
(x-4)(x+1)=0
The solution is C = {- 1,4}
B∪C=｛-4,-1,2,4｝
A∩(B∪C)={2}

Solve the system of inequalities: 3x − 2 ≤ x + 65x + 32 > X

3x−2≤x+6… ①5x+32＞x… ② Then the solution set of the inequality is: - 1 < x ≤ 4

On line and so on, urgent, factorization related topics
1. If a = - 5, a + B + C = - 5.2, find the value of algebraic formula A to the second power (- B-C) - 3.2a (c + b)
2. Given a + B = 10, ab = 6, find: a (cubic) b-2a (quadratic) B (quadratic) + AB (cubic is only b)
3. It is known that a, B and C are three sides of a triangle respectively, then (a 2 times + B 2 times - C 2 times) is 2 times - 4a2 times and B2 times

1)A=-5,B+C=-0.2
Original formula = - A ^ 2 (B + C) - 3.2a (c + b)
=1.8
2) Original formula = AB * (a ^ 2-2ab + B ^ 2)
=ab*(a-b)^2
(a-b)^2=(a+b)^2-4ab=76
Answer = 456

On factorization,
Given that x minus y equals 2, the square of x plus the square of Y equals 16, find the value of XY

x-y=2
The square of the two sides is as follows:
x^2-2xy+y^2=4
xy=(x^2+y^2-4)/2=(16-4)/2=6

Please factorize the following questions
1.2(a-3)(a-3)-a+3
2.9(m+n)(m+n)-16(m-n)(m-n)
3.15(a-2)-9b(a-1)(2-a)
4.16a×a×a×a-72a×a×b×b+81b×b×b×b

9(a-b)(a+b)-3(a-b)^2

a(b^2-c^2)+b(a^2-c^2)+c(a^2-b^2)

The original formula = AB ^ 2-ac ^ 2 + Ba ^ 2-bc ^ 2 + Ca ^ 2-cb ^ 2 = AB (a + b) - AC ^ 2 + Ba ^ 2-bc ^ 2 + Ca ^ 2-cb ^ 2 = AB (a + b) - (a + b) C ^ 2 + Ca ^ 2-cb ^ 2 = AB (a + b) - (a + b) C ^ 2 + C (a ^ 2-B ^ 2) = AB (a + b) - (a + b) C ^ 2 + C (a + b) (a-b) = (a + b) (ab-c ^ 2 + AC BC) = (a + b) [a (B + C) - C (B + C)] = (a + b) (a + b) = (a + b) = (a + b) = (a + b) = (a + b) = (a + B) = (a + b) = (a + b) = (a + b) = (a + b) = (a

-1 / 2A cube B + 2Ab cube
N + 1 times of a-n-1 times of A-4 times of B

-(1/2)a³b+2ab³=2ab(b²-a²)=2ab(b+a)(b-a)aⁿ⁺¹-aⁿ⁻¹b⁴=aⁿ⁻¹(a²-b⁴)=aⁿ⁻¹(a+b²)(a-b²)

Factorization of two elementary schools
1、x^3（a-2b）+x^2（2b-a）
2、3x（x-y）^3-6xy（y-x）^3

1、x^3（a-2b）+x^2（2b-a）
=X³(a-2b)-X²(a-2b)
=X²(a-2b)(X-1)
2、3x（x-y）^3-6xy（y-x）^3
=3x(x-y)³+6xy(x-y)³
=3x(x-y)³(1+2y)
What do you don't understand