Set u = {x | x ≤ 10 and X ∈ n +}, a is the proper subset of u, B is the proper subset of u, and a ∩ B = {4,5}, (cub) ∩ a = {1,2,3}, (CUA) ∩ (cub) = {6,7,8}, find sets a and B

Set u = {x | x ≤ 10 and X ∈ n +}, a is the proper subset of u, B is the proper subset of u, and a ∩ B = {4,5}, (cub) ∩ a = {1,2,3}, (CUA) ∩ (cub) = {6,7,8}, find sets a and B

A=(A∩B)U((CuB）∩A)==｛1,2,3,4,5｝
Cub = ((CUA) ∩ cub)) U ((cub) ∩ a) = = {1,2,3,6,7,8} so B = = {4,5,9,10}

Let u = {X / X be less than 10, and X belong to n}. A intersection B = {5,6} and (CUA) intersection B = {2}, and (CUA) intersection (cub) = {4,8,9} find the set a and B. find the large

A={0,1,3,5,6,7},B={2,5,6}

Let u = R, a = {x | x ≠ 1}, then CUA =?

CUA denotes the complement of a on the complete set R
That is, CUA = {x | x square = 1} = {- 1,1}

There are several questions about factoring that I can't do
25b³-80b²+64b=
x²-4（x-1）=
16x⁴-72x²y²+81y⁴
87²+87×26+13²

25b³-80b²+64b=b(25b²-80b+64)=b(5b-8)²x²-4（x-1）=x²-4x+4=(x-2)²16x⁴-72x²y²+81y⁴=(4x²-9y²)²=(2x+3y)²(2x-3y)²87²+87...

Given a & # 178; + B & # 178; - 4a-6b + 13 = 0, find the value of a + B
（ay+bx）³-（ax+by）³+（a³-b³）（x³-y³）
x4+x³+2x²+x+1
Given that n is a positive integer and n4-16n & # 178; + 100 is a prime number, then n =?
（1+y）²-2x²（1+y²）+x4（1-y）²
-a4-b4-c4+2a²b²+2b²c²+2a²c²
x³+3x²-4
x4+2x³-9x²-2x+8
a³+3a²+3a+b³+3b²+3b+2
x²-y²+2x+6y-8
-14x²y²+x4+y4
x4-47x²+1
x4+1/4y4
The more you answer, the faster you get!

a²+b²-4a+6b+13=（a-2）²+（b+3）²=0∴a=2,b=-3a+b=-1（ay+bx）³-（ax+by）³+（a³-b³）（x³-y³）=（ay+bx-ax-by）[（ay+bx）²+（ay+bx）（ax+by）+（ax+by...

+6x³+11x+6（1+y）²-2x²（1+y²）+x4（1-y）²
x4-2（a²+b²）x²+（a²-b²）²
x³（a+1）-xy（x-y）（a-b）+y³（b+1）
x4+4y4
x4+64
x³+2x²-6-5x
x³+6x-7
x³-9x+8
x³+6x³+11x+6

The first question is not complete. Please add. The rest questions are very simple. I'll give them to you after I do them
x4-2﹙a²+b²)x²+(a²-b²)²
=x4-2﹙a²+b²)x²+(a²+b²)²-4a²b²
=[x²-(a²+b²)]²-4a²b²
=[x²-(a²+b²)+2ab][x²-(a²+b²)-2ab]
=[x²-(a²-2ab+b²)][x²-(a²+2ab+b²)]
=(x+a-b)(x-a+b)(x-a-b)(x+a+b)

1 x²y-3xy²
2 2x(2x-y)+y(y-2x)
3 -6x(m-2n)+12(2n-m)
4 3(y-x)²-(x-y)³
5 4a²-36
6 (x-2y)²-x²
7 4x³y+4x²y²+xy³
8 (x+y)²-2m(x+y)+m²
9 x²-9x+18
10 -8x²-10x-3

1 x²y-3xy²=xy(x-3y)2 2x(2x-y)+y(y-2x)=(2x-y)(2x-y)=(2x-y)²3 -6x(m-2n)+12(2n-m)=(2n-m)(12+6x)=6(2n-m)(2+x)4 3(y-x)²-(x-y)³=(x-y)²(3-x+y)5 4a²-36=4(a+3)(a-3)6 (x-2y)&#...

1.m(x-y-z)+n(y+z-x)=(x-y-z)*?
2.x^2-(a+1)x+a+?
3.6x^2+7x+2=?

1.m(x-y-z)+n(y+z-x)=(x-y-z)*(m-n)
2.x^2-(a+1)x+a=(x-1)(x-a)
3.6x^2+7x+2=(2x+1)(3x+2)

Factorization by grouping
x^2-25+y^2-2xy

x^2-25+y^2-2xy
= x^2+y^2-2xy -25
= (x-y)^2 -5^2
= (x-y+5) (x-y-5)

[group decomposition method (factorization)]
（1）a²-3a+b²-3b+2ab-54（2）x²+8xy+16y²+3x+12y+2
（3）4-a²+4ab-4b²（4）x²+4y-1-4y²

（1）a²-3a+b²-3b+2ab-54=（a²+2ab+b²）+（-3a-3b)-54=(a+b)²-3(a+b)-54=(a+b+6)(a+b-9)（2）x²+8xy+16y²+3x+12y+2=(x²+8xy+16y²)+(3x+12y)+2=(x+4y)²+3(x+4y)+2...