The decomposition factor X (X-Y) & #178; - Y (X-Y) & #178; (2a + b) (2a-3b) - 3A (2a + b) of junior high school mathematics problems Factorization of junior high school mathematics problems x(x-y)²-y(x-y)² (2a+b)(2a-3b)-3a(2a+b) x(x+y)(x-y)-x(x+y)²

The decomposition factor X (X-Y) & #178; - Y (X-Y) & #178; (2a + b) (2a-3b) - 3A (2a + b) of junior high school mathematics problems Factorization of junior high school mathematics problems x(x-y)²-y(x-y)² (2a+b)(2a-3b)-3a(2a+b) x(x+y)(x-y)-x(x+y)²

1. (X-Y) cubic

Given the complete set u = {1,2,3,4,5}, a = {X / x ^ - 5x + M = 0}, B = {X / x ^ + NX + 12 = O}, and (CUA) UB = {1,3,4,5}, find the value of M + n
It's a little urgent

∵（CuA）UB={1,3,4,5}
2 belongs to a
Substituting 2 into a: 4-10 + M = 0, M = 6
A=｛2,3｝
3 belongs to B
Substituting 3 into B 9 + 3N + 12 = 0, n = - 7
∴m+n=-1

F (x) = x & # 178; - 5x + 4, G (x + 1) = f (x), then G (x) = ()

Let a = x + 1
Then x = A-1
g(a)=f(a-1)
So g (x) = f (x-1)
=(x-1)²-5(x-1)+4
=x²-7x+10

Please help me to solve a math problem 2 (5x-1) & # = 3 (5x-1) with cross multiplication

2(5X-1)²=3(5X-1)
Simplify 10x & # 178; - 7x + 1 = 0
The cross is multiplied as follows
-2X 1
-5X 1
■ - 2x + 1 = 0 or - 5x + 1 = 0
The solution is x = 1 / 2 or x = 1 / 5

There are two factoring problems. Who can help me?
(a-b)(a^2-ab+b^2)-ab(a-b)；(x+y)^2+4(x-y)^2-4(x^2-y^2)

I'll help you to answer online. But I'm also answering. You can contact me online. Let's take a look at the sofa first
1=(a-b)(a^2-ab+b^2-ab)
=(a-b)(a-b)^2=(a-b)^3
2=(x+y)^2+4(x-y)^2-4(x+y)(x-y)
=[(x+y)+2(x-y)]^2=(3x-y)^2

Two questions, factorization
1. It is shown that no matter what number x and y are, the algebraic formula X & sup2; - 4x + Y & sup2; - 6y + 15 is always positive
2. It is known that three sides a, B and C of △ ABC satisfy a & sup2; - B & sup2; - AC + BC = 0 to judge the shape of △ ABC
I've learned to add points
.

1. Divide 15 into 4 + 9 + 2x & sup2; - 4x + Y & sup2; - 6y + 15 = x & sup2; - 4x + Y & sup2; - 6y + 4 + 9 + 2 = (X & sup2; - 4x + 4) + (Y & sup2; - 6y + 9) + 2 = (X-2) & sup2; + (Y-3) & sup2; + 2, so (X-2) & sup2; + (Y-3) & sup2; > = 0, so (X-2) & sup2; + (Y-3) & sup2; + 2 >

1.（a²+b²）²-4a²b²
2.-x（x-y）+x²（y-x）

1.（a²+b²）²-4a²b²
=(a²+b²+2ab)(a²+b²-2ab)
=(a+b)²(a-b)²
2.-x（x-y）+x²（y-x）
=x(y-x)+x²(y-x)
=x(y-x)(1+x)

① Factorization is inversely related to integral multiplication. Please use a & # 178; - B & # 178; = (a + b) (a-b) to calculate 999.9 & # 178; - 0.1 & # 178
② Given that 2x-y = 1 / 3, xy = 2, find the power of 2x to the fourth power of Y & # 179; - X & # 179; y
③ Decompose factor X & # 178; + ax + B, a misread the value of a, the result of decomposition is (x + 6) (x-1), B misread the value of B, the result of decomposition is (X-2) (x + 1), find the value of a + B

①999.9²-0.1²
=﹙999.9+0.1﹚﹙999.9-0.1﹚
=999.8×1000
=999800
②2x^4y³-x³y^4
=x³y³﹙2x-y﹚
=2³×3
=24
③ (x + 6) (x-1) = x & # 178; + 6x-x-6 = x & # 178; + 5x-6 a misread the value of a, B = - 6
(X-2) (x + 1) = x & # 178; - 2x + X-2 = x & # 178; - X-2 B misread the value of B a = - 1
a+b=-1-6=-7

X Cubic - 2x square y + XY square
4A square-2a-b square-b
3Y square + 11y + 10
2A (x square + 1) square - 8ax square

x^3-2x^2y+xy^2=x(x^2-2xy+y^2)=x(x-y)^24a^2-2a-b^2-b=4a^2-b^2-2a-b=(2a+b)(2a-b)-(2a+b)=(2a+b)(2a-b-1)3y^2+11y+10=(y+2)(3y+5)2a(x^2+1)^2-8ax^2=2a[(x^2+1)^2-4x^2]=2a[(x^2+1+2x)(x^2+1-2x)]=2a(x+1)^2(x-1)^...

（1）4b²-10b+c²-5c+4bc+6
（2）2x²-xy+3x-y+1
（3）a²-c²+2ab+b²-d²-2dc
（4）x²-2xy+y²+2x-2y
（5）a²-2ab+b²-4c²
(6) Given x + 2Y + 1 = 0, find the value of X & # 178; + xy-2y & # 178; + 3x + 3Y + 2

（1）4b²-10b+c²-5c+4bc+6=(4b²+c²+4bc)-5(2b+c)+6=(2b+c)²-5(2b+c)+6=(2b+c-2)(2b+c-3)
（2）2x²-xy+3x-y+1
=2x²+3x+1-y(x+1)
=(2x+1)(x+1)-y(x+1)
=(x+1)(2x+1-y)
（3）a²-c²+2ab+b²-d²-2dc
=(a+b)²-(c+d)²=(a+b+c+d)(a+b-C-d)
（4）x²-2xy+y²+2x-2y
=(x-y)²+2(x-y)=(x-y)(x-y+2)
（5）a²-2ab+b²-4c²
=(a-b)²-4c²
=(a-b+2c)(a-b-2c)
(6) Given x + 2Y + 1 = 0, find the value of X & # 178; + xy-2y & # 178; + 3x + 3Y + 2
x²+xy-2y²+3x+3y+2=(x+2y)(x-y)+3x+3y+2=-1（x-y)+3x+3y+2=-x+y+3x+3y+2=2x+4y+2=0