A mathematical problem about golden section It is known that P and Q are the golden section points of line AB, and PQ = 2cm The answer is (root 5 + 4) / 2, but how is it calculated? I hope you can help me explain,

A mathematical problem about golden section It is known that P and Q are the golden section points of line AB, and PQ = 2cm The answer is (root 5 + 4) / 2, but how is it calculated? I hope you can help me explain,


AP:PB:AB=1:K:K^2
PQ=PB-PA=AB[(K/K+1)-(1/K+1)]=AB*(K-1)/K+1=2
K is the golden section ratio
It can be worked out



The golden section
1. Given that the line segment AB = 1, points c and D are its two golden section points respectively, then the length of CD is ()
2. If the ratio between the bottom and the waist of an isosceles triangle whose vertex angle is 36 degrees is the golden ratio, then the triangle ()


1. Given that the line segment AB = 1, points c and D are its two golden section points respectively, then the length of CD is (0.34)
2. If the ratio between the bottom and the waist of an isosceles triangle with a vertex angle of 36 degrees is the golden ratio, then the triangle does not exist