Solution of binary linear equation [x + y] X1 = 6 x-yx3 = 6

Solution of binary linear equation [x + y] X1 = 6 x-yx3 = 6

The formula x + y = 6.1 is obtained
Formula x-3y = 6.2
Formula 1-2, get
4Y=0
The solution is y = 0
By substituting y = 0 into 1
X=6

The solution formula of quadratic equation of two variables,
x+y=80190.6
3.6x+2y=277316.54
x? y?

x+y=80190.6 =>2x+2y=160381.2 1)
3.6x+2y=277316.54 2)
2) - 1)
1.6x=116935.34
x=73084.5875
y=80190.6-73084.5875=7106.0125

The process of adding and subtracting, bringing in and solving equations in elimination of quadratic equations of two variables

The addition and subtraction method in elimination of quadratic equation of two variables: 1. An equation is established only when both sides of the equation multiply the same number
Two equations can be multiplied by different numbers, such as
2x+3y=7－－－（1）
5x-y=9－－－－（2）
If we find x first, because the coefficients in front of the two equations X have the same sign, we use subtraction
(1)×5-(2)×2
15y-(-2y)=7×5-9×2
17Y = 17, y = 1, x = 2
If you find y first, because the sign of the coefficients in front of the two equations y is opposite, add them
(1)+(2)×3
2x+15x=7+9×3
17x = 34, x = 2, y = 1
2. If I encounter binary linear equations of fractions, I usually convert the equations with fractions as coefficients into integer coefficients and then solve them, such as
(1/3)x+(2/5)y=15
(1/2)y+(4/6)x=10
Multiply both sides of the first equation by 15 (because 15 is the least common multiple of 3 and 5)
5x+6y=225
The second equation is multiplied by 6 (6 is the least common multiple of 2 and 6)
3y+4x=60