68-4.4X=24 8y-4×14=0 x+3.5×3=18 It's three questions, not one,

68-4.4X=24 8y-4×14=0 x+3.5×3=18 It's three questions, not one,

68-24=4.4X
44=4.4x
x=10
8y-56=0
8y=56
y=7
x+10.5=18
x=7.5
How do you always feel guilty

Given the equations 4x + 2Y = 1,20x + 8y, find x, y
20x+8y=1，sorry

X=-3/4 y=2

X ^ 2-xy + y ^ 2 = 7 when x = 2, find the curve equation and normal equation

Let f (x, y) = x ^ 2-x * y + y ^ 2-7, Let f (x, y) = 0, and substitute x = 2 to get y = - 1, y = 3. By using f (x, y) to obtain partial derivatives of X and Y respectively, we can get dy / DX = (- f '(x, y) | x) / (f' (x, y) | y) = (2 * X-Y) / (X-2 * y). Substituting x = 2, y = - 1 and x = 2, y = 3 to get dy / DX = 5 / 4 or dy / DX = - 1 / 4, then there are two

The curve represented by x ^ 2-xy + 3Y ^ 2-1 = 0 is symmetrical about the origin but not about the coordinate axis. Why?

In the original equation, if we change x to - X and y to - y at the same time, the equation remains unchanged, then the curve is symmetric about the origin
In the original equation, if x is replaced by - x, the equation is changed, so the curve is asymmetric about the Y axis,
In the same way, if y is replaced by - y, the equation will also change, so the curve is asymmetric about X axis

The curve equation of x ^ 2-y ^ 2-4x + 2y-3 = 0 with respect to the origin symmetry is?
How can there be a curve of type X ^ 2-y ^ 2? What graph is it?
What graph is this equation? What do the coefficients represent?

x^2-y^2-4x+2y-3=0
(x-2)^2-(y-1)^2=6
(X-2) ^ 2 / 6 - (Y-1) ^ 2 / 6 = 1 (hyperbola)
On the symmetric curve of origin
(x+2)^2/6-(y+1)^2=6
That is, (x + 2) ^ 2 - (y + 1) ^ 2 = 6 (hyperbola)

The curve which is centrosymmetric to the curve 2x ^ 2 + XY + SiNx = 0 about the origin is

Let P (x, y) be any point on the curve. Since the curve and the curve 2x & # 178; + XY + SiNx = 0 are centrosymmetric with respect to the origin, the point P (x, y) symmetric with respect to the origin (- x, - y) is on the curve 2X & # 178; + XY + SiNx = 0. Substituting the coordinates (- x, - y) into the known curve equation 2x & # 178; + XY + SiNx = 0, we can get: 2 (- x) &

Solving the equation of the curve xy-y-1 = 0 symmetric to the line x + Y-5 = 0

Let (x0, Y0) be a point on xy-y-1 = 0, and the symmetric point on the straight line x + Y-5 = 0 is: (a, b) (y0-b) / (x0-a) = 1 (x0 + a) / 2 + (Y0 + b) / 2-5 = 0. The simultaneous solution of a = 5-y0, B = 5-x0 is obtained by substituting a = 5-y0, B = 5-x0 into xy-y-1 = 0 (5-y0) (5-x0) - (5-x0) - 1 = 0, and the simplified equation is: 4x0 + 5y0-x0y0-19 = 0

Let u = {x | 0
————B = {X2 (square) + PX + 12 = 0}

From the complete set u = {x | 0

Let the set u = {12345}, a = {x | x2-5x + a = 0}, and the empty set is really contained in a, a is really contained in U, find the value of a and the complement of A

An empty set is really contained in a, and a is really contained in U
This sentence shows that the equation x2-5x + a = 0 has a solution, and the solution is one or two of U
So there is
5*5-4*1*a>=0
Get a range of A
Then you take the numbers in u one by one and get a, which is the value of a in accordance with the range just found
Do you know the complement of a?

Given the complete set u = {x | x ∈ N and X ≤ 5}, a = {x | X - 5x + a = 0, X ∈ u} find the complement of A

Because the complete set u = {x | x ∈ N and X ≤ 5} = {0,1,2,3,4,5}, a = {x | X - 5x + a = 0, X ∈ u} (1) 0 or 5 belongs to a, substituting a = 0 into the equation of a, then a = {0,5}, so CUA = {1,2,3,4} (2) 1 or 4 belongs to a, substituting a = 4, then a = {1,4}, so CUA = {0,2,3