3 (2.8 + x) = 27.6, please tell me!

3 (2.8 + x) = 27.6, please tell me!

8.4+3x=27.6
3x =27.6-8.4
3x =19.2
x =19.2 / 3
x =6.4

If (27 ^ - x) ^ 2 = 3 ^ 8, then x=_______

(27^-x)^2=27^-2x=(3^3)^-2x=3^-6x=3^8
So - 6x = 8
x=-4/3
If (27 ^ - x) ^ 2 = 3 ^ 8, then x=___ -4/3____

-8(x-2)3^=27

-8(x-2)3^=27
(x-2)³=-27/8
x-2=-3/2
x=1/2

Find the value of X in the following formulas: (1) 16x2-361 = 0; (2) - 8 (x-3) 3 = 27

（1）x2=36116x=±194；（2）（x-3）3=-278．x-3=-32x=32．

If (27 / 8) ^ X-1 × (2 / 3) ^ 2x-3 = 4 / 9, then x=

x=-2

8（ X-3）-5X=27…… Help answer

8（ X-3）-5X=27
8x-24-5x=27
3x=27+24=51
x=17
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How to solve 8 (x-3) - 5 = 27

First, multiply the number outside the brackets by the number in the brackets 8x-3 * 8-5 = 27
8x-24-5＝27
8x-24+24-5+5 ＝27+24+5
8x＝56
x＝7
We didn't need + 24 and + 5, but our teacher in Grade 7 asked us to do it, so we did it
I'm in the same grade as you

27*（x-1）3=8

It can be regarded as 81 (x-1) = 0

(x ^ 2 + y ^ 2) ^ 2-4x ^ 2Y ^ 2 calculated by decomposition factor

Original formula = (x ^ 2-y ^ 2) ^ 2
=(x+y)^2(x-y)^2
Formula: (x + y) ^ 2-4xy = (X-Y) ^ 2 this formula can be derived by itself

To solve a mathematical problem, calculate (x + 2Y) & sup2; (x-2y) & sup2; with the square difference formula

The original formula = [(x + 2Y) (x-2y)] & sup2;
=(x²-4y²)²
=X4 power - 8x & sup2; Y & sup2; + 16y4 power