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How much is the Y power of X equal to if the square of x plus the square of Y minus 4x plus 5 equals 0?
The title is wrong, it should be: X & # 178; + Y & # 178; - 4x-5 = 0x & # 178; + Y & # 178; - 4x-5 = 0x & # 178; - 4x + 4 + Y & # 178; - 9 = 0 (X-2) &# 178; + (Y-3) (y + 3) = 0 X-2 = 0, Y-3 = 0, y + 3 = 0 x = 2, Y1 = 3, y = - 3, y = - 3, y power of x = 2 & # 179; = 8 or Y power of x = 2 ^ (- 3) = 1 / 8
Using the formula of logarithm to find the value of log (2) 25 multiplied by log (3) 4 multiplied by log (5) 9 is equal to? Prove: log (a) B multiplied by log (b) C multiplied by log (c) a = 1
Log (2) 25 multiplied by log (3) 4 multiplied by log (5) 9 equals? = LG25 / LG2 × LG4 / Lg3 × lg9 / lg5 = 8lg5 / LG2 × LG2 / Lg3 × Lg3 / lg5 = 8 prove: log (a) B multiplied by log (b) C multiplied by log (c) a = 1, left = LGB / LGA × LGC / LGB × LGA / LGC = 1, right = 1 Change the formula loga B = LGB / LGA to
Simple calculation with factorization method
1、 12.5 ^ 2-12.5 × 5 + 6.25 2.21.5 ^ 2-3 × 21.5 + 1.5 ^ 2-100 3.125 × 0.45-12.5 × 6.7 + 1.25 × 122
We need to use some formulas: A ^ 2-2ab + B ^ 2 = (a-b) ^ 2, a ^ 2-B ^ 2 = (a + b) (a-b), AB + AC + ad = a (B + C + D)
1) 12.5^2-12.5*5+6.25
=12.5^2-2*12.5*2.5+2.5^2
=(12.5-2.5)^2
=10^2
=100
2) 21.5^2-3*21.5+1.5^2-100
=21.5^2-2*21.5*1.5+1.5^2-100
=(21.5-1.5)^2-100
=20^2-10^2
=(20+10)(20-10)
=30*10
=300
3) 125*0.45-12.5*6.7+1.25*122
=12.5*4.5-12.5*6.7+12.5*12.2
=12.5*(4.5+12.2-6.7)
=12.5*10
=125
Find the factorization of quadratic equation of one variable!
3X^2-12X=-12
3X(X -1)=2(X-1)
(2X-1)^2=(3-X)^2
3X^2-12X=-12 3X^2-12X+12 =0x^2-4x+4=0(x-2)^2=0x1=x2=23X(X -1)=2(X-1)3X(X -1)-2(X-1)=0(x-1)(3x-2)=0x1=1x2=2/5(2X-1)^2=(3-X)^2 (2X-1)^2-(3-X)^2 =0(2x-1+3-x)(2x-1-3+x)=0(x+2)(3x-4)=0x1=-2x2=4/3
Factorization factor (a + b-2ab) (a + b-2) + (1-ab) & # 178; using the method of substitution
I'll be back in a minute
（a+b-2ab)(a+b-2)+(1-ab)²
Let a + B = x, ab = y
(x-2y)(x-2)+(1-y)²
=x²-2x-2xy+4y+1-2y+y²
=x²-2xy+y²-2x+2y+1
=（x-y）² -2(x-y)+1
=(x-y-1)²
=(a+b-ab-1)²
=[(a-1)(1-b)]²
=(a-1)²(1-b)²
How to use factorization to solve cubic equation of one variable?
Take the solution of a & # 179; - 2A & # 178; - A + 7 = 5 as an example
a³-2a²-a+7=5
a³-2a²-a+2=0
(a³-a)-2(a²-1)=0
a(a²-1)-2(a²-1)=0
(a²-1)(a-2)=0
(a+1)(a-1)(a-2)=0
A = - 1 or a = 1 or a = 2
For example, how to find the root of 2x ^ 2-3x ^ 2-3x + 2 = 0? How to factorize? Is there a general rule?
The wrong number is 2x ^ 3-3x ^ 2-3x + 2 = 0
In high school, it is not required to master the root formula of cubic equation (Cardin formula). Generally, one root is obtained by trial root method, and then the other two roots are obtained by decomposition. Trial root method is mainly based on the following rules: if the equation has rational root M / N, then M is the factor of constant term, and N is the factor of the highest term coefficient
The third power of 3x - the second power of 12xy
The second power of (3x + 2Y) and the second power of - (2x + 3Y)
The second power of (2a + b) - (2B + a)
-The second power of 8a, the second power of B - the second power of 4A, B + 2Ab
fifty-five trillion and five hundred and fifty-five billion five hundred and fifty-five million five hundred and fifty-five thousand five hundred and fifty-five
Refer to the third answer, if it is 4 questions: the steps are as follows:
1 = 3x (power 2 of X - power 2 of 4 * y)
=3X（X-2Y）（X+2Y）
Let 3x + 2Y = a, 2x + 3Y = B
Then there is (a-b) (a + b)
Then the original formula = (3x + 2y-2x-3y) (3x + 2Y + 2x + 3Y)
=(X-Y)(5X+5Y)
=5(X-Y)(X+Y)
Let 2A + B = x, 2b + a = y
Then the original formula = the second power of X - the second power of Y
=（X-Y）（X+Y）
Take the equation into the equation
=(2a+b-2b-a)(2a+b+2b+a)
=(a-b)(3a+3b)
=3(a-b)(a+b)
4 =-2ab(4ab+2a-1)
Two ways of factorization in grade one of junior high school
x^2-xy-2y^2-3x+2
x^3+x^2-4x+2
=x²-2xy-2x+xy-2y²-2y-x+2y+2=x(x-2y-2)+y(x-2y-2)-(x-2y-2)=(x-2y-2)(x+y-1)=x³-x²+2x²-2x-2x+2=x²(x-1)+2x(x-1)-2(x-1)=(x-1)(x²+2x-2)
(xsquare - 9ysquare) - (x + 3Y)
Using the square difference formula
(x+3y)(x-3y)-(x+3y)
（x+3y)²-（x-3y)
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