Please construct 5 prime numbers with tolerance of 12

Please construct 5 prime numbers with tolerance of 12

Of prime numbers, only 2 is even
It is constructed from 2, and the second one is even, which is not consistent with the title
So all prime numbers are odd
If the first bit is 1,1 + 2 = 3,3 + 2 = 5
The third digit is 5, which is divisible by 5
If the first bit is 3,3 + 2 = 5, it can be divided by 5
If the first digit is 7,7 + 2 = 9,9 + 2 = 11,1 + 2 = 3,3 + 2 = 5, it does not conform to the meaning of the title
If the first digit is 9,9 + 2 = 11,1 + 2 = 3,3 + 2 = 5, it does not conform to the meaning of the title
Just now I forgot to consider the case of a bit 5
5 itself is prime
5+12=17
17+12=29
29+12=31
31+12=43
These five prime numbers are 5, 17, 29, 31 and 43

Xiao Ming walked 32km on the first day, 41km on the second day, 44km on the third day, and 9km more on the fourth day than the average of the four days
PS: the problem is basically like this, the difficulty is that we can't set X to solve it, we can only use the formula to deduce it, and ask enthusiastic friends to help us solve it
We can't set up the equation of unknown number X. we can only use the formula to calculate the result step by step before we reach that grade

The new average of the first three days is (32 + 41 + 44 + 9) / 3 = 126 / 3 = 42, that is, the average of the fourth day is 42, so the road of the fourth day is 42 + 9 = 51km

There are several liters of 3% salt water, and after adding a cup of water, the concentration becomes & nbsp; 2%___ A glass of water

Let the raw brine be x cup, and the result is: 3% X ÷ (x + 1) = 2% & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.03x = 0.02 × (x + 1) & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.01x = 0.02 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 2. Add water: 3% ×

Factorize the following equation a ^ 3-2a ^ 2-A + 2
Such as the title

a^3-2a^2-a+2
=a²（a-2）-(a-2)
=(a²-1)(a-2)
=(a+1)(a-1)(a-2)
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How to factorize 18 (a + b) ^ 3 + 2B (B-A) ^ 2

Factorization a ^ 2B ^ 2-8ab + 7

1 -1
1 -7
----------------
a^2b^2-8ab+7=（ab-1)(ab-7)

Factorization a ^ 4-8 * a ^ 2 * B ^ 2 + 1

a^4-8*a^2*b^2+1
=a^2(a^2-8*b^2)+1
=A ^ 2 (a + 2 times root 2 * b) (A-2 times root 2 * b) + 1

81 (a + b) ^ 2-4 (a-b) ^ 2

81（a+b)^2-4(a-b)^2
=[9(a+b)+2(a-b)][(9(a+b)-2(a-b)]
=(11a-7b)((7a+11b)

X ^ 4-2 (a ^ 2 + B ^ 2) x ^ 2 + (a ^ 2-B ^ 2) 2, factorization,

Factorization of x ^ 2 - (a + B-C) ^ 2

x^2-(a+b-c)^2
=(x+a+b-c)(x-a-b+c)