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Solving the equation with (3x-4) × 5 = 4
eight
15x-8-2 times (4.3x + 1)
15x-8 = 2 times (4.3x + 1)
15x-8＝8.6x+2
15x-8.6x=8+2
6.4x=10
x=10/6.4
x=1.5625
The solution of equation 3x ^ 2-15x-2 √ (x ^ 2-5x + 3) + 8 = 0 is
The answer is known as (5 ± √ 17) / 2
3x^2-15x-2√(x^2-5x+3)+8=0
3(x^2-5x+3)-2√(x^2-5x+3)-1=0
Let y = √ (x ^ 2-5x + 3) ≥ 0
3y^2-2y-1=0
(3y+1)(y-1)=0
y=1
√(x^2-5x+3)=1
x^2-5x+3=1
x^2-5x+2=0
x=(5±√17)/2
How to solve 10x + 7 = 14x-5-3x
10x+7=14x-5-3x
14x-3x-10x=7+5
x=12
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