If the distance between the image of the linear function y = KX + 6 and the two intersections of the coordinate axis is 10, then the value of K is 0

When x = 0, y = 6
When y = 0, x = - 6 / K
It can be seen that the two intersections are (0,6) and (- 6 / K, 0) respectively
We can use Pythagorean theorem to calculate a right side of a right triangle
（-6/k）²+6²=10²
The solution is k = ± 3 / 4

In the rectangular coordinate system, the line L intersects the y-axis at the point (0, - 1) and the x-axis at the point (2 / 3,0)
The previous "line L intersects Y-axis at point (0, - 1), intersects X-axis at point (2 / 3, 0)" is changed to“
Line L intersects Y-axis at point (0,1) and X-axis at point (2 / 3,0)

If Y-axis intersects at point (0, - 1), then B = - 1
Y = kx-1, then passing through the point (2 / 3,0)
0 = 2 / 3K-1, so k = 3 / 2
So y = (3 / 2) * X-1

It is known that the images of the inverse scale function y = x / A and the first-order function y = KX + B pass through two points (2, - 1) (1, c)

Take (2, - 1) into y = a of X to get
a=-2
So y = - 2 / X
Take x = 1 into y = - 2 / X to get
y=-2
So C = - 2
Take (2, - 1) (1, - 2) into y = KX + B to get
{-1=2k+b
{-2=k+b
The solution is k = 1
b=-3
So answer: the analytic formula of inverse proportion function is y = - 2 / x, and the analytic formula of primary function is y = x-3

It is known that the image of the first-order function y = KX + B (K ≠ 0) passes through the point (0,1), and Y decreases with the increase of X. please write out a functional relation that meets the condition
It is known that the image of the first-order function y = KX + B (K ≠ 0) passes through the point (0,1), and Y decreases with the increase of X. please write a functional relation that meets the above conditions

The image of function y = KX + B (K ≠ 0) passes through point (0,1)
So substituting the point into the function, we get b = 1
Y decreases with the increase of X, so K

If the image of the first-order function y = KX + B passes through (3,0) points, and when x < 3, Y > 0, try to write the first-order function relation satisfying the above conditions

Straight line (3,0)
So its analytical formula is y = KX + 3
Substituting x = 3, y = 0 into y = KX + 3, we can get k = - 1
Therefore, the linear functional relation satisfying the above conditions is
y=-x+3

1. Given that the image of y = KX + B passes through (0,2) and is parallel to the line y = - 2x + 1, then the function relation is
2. Given that a line passes through (0,0), (1, - 2), find the function expression of the line
3. Given the linear function y + (M + 3) x + (2-N), what are the values of M and N, the intersection of yuy axis of image is above X axis?

1、y=-2x+2
2、y=-2x
3. M can be any value, n

It is known that the straight line y = KX + B is parallel to the straight line y = - 2x + 99, and through the point P (- 1, - 4), we can find (1) the relationship of the first-order function, (2) the image of the first-order function and the sitting position
The area of the figure enclosed by the axis

The two lines are parallel, the slope is equal, k = - 2
Substituting point P into the linear equation, we get b = - 2
The intersection coordinates of the line and the coordinate axis are (0, - 2) (- 1,0)
The area is 1

If the image of a function y = KX passes through point (3, - 2), the expression of this function is

y=-2x/3

1) Find the function expression of the line L passing through the point P (1,4) and parallel to the known line y = - 2x-1, and draw the image of the line L. (2) let
1) Find the function expression of the line L parallel to the known line y = - 2x - 1 through the point P (1,4), and draw the image of the line L
(2) Let the line L intersect with the y-axis at points a and B respectively. If the line M: y = KX + T (T > 0) is parallel to the line L and intersects with the x-axis at point C, the functional expression of the area s of △ ABC with respect to t is obtained
The second question! Just answer the second question, good answer 50 points, don't break your promise!

The analytic formula of L1 is y = 2x + 2. If it intersects with X-axis at a (- 1,0), with Y-axis at B (0,2), and the line y = KX + T is parallel to L1, then k = 3, that is, y = 3x + T. If it intersects with X-axis at C (- t / 3,0), triangle ABC area s = 1 / 2 (T / 3 + 1) × 2 = 1 / 3T + 1.. so s = 1 / 3T + 1

Given that a function image passes through the intersection of the line y = - x + 3 and the X axis, and the ordinate of the intersection with the Y axis is - 2, the function expression is obtained
This is the problem of determining the expression of a function!

Function expression:
y=2/3x-2

If the distance between the image of the linear function y = KX + 6 and the two intersections of the coordinate axis is 10, then the value of K is 0