The process of solving the system of equations y = 2x-3 3x-2y = 5

y=2x-3 （1）
3x-2y=5（2）
(1) Substitute (2) to get
3x-2(2x-3)=5
x=1
Substitute (1) to get
y=2-3=-1

Find 10 to the denominator of the equation of one variable, urgent

5x+2(2x/3+2)=2/3(x-6)+2 (2x-7)/2-(6x-5)/3=2x+3 (3x+2)/5-(x-6)=x/3 6x-(x/3+2)=2(x/5+5/2)-3 3(x/11-2)-5=2+3x/3 10/3(2x-6)=3/5 x/2-(x/3-2)=3 2/3(x+3)-3=5x/3 5/3(2x-5/3)=2x/5-8/9 25(x/3-x/2+2/5)-2=3/5(x-2/7)+4/9

How to do when the denominator of mathematical equation of one variable is a decimal

When the denominator is a decimal, the basic property of the fraction (the numerator denominator is multiplied by a number that is not equal to zero) is used to convert the decimal into an integer
Go to the denominator
Specifically, when the denominator is a decimal, the numerator and denominator are multiplied by 10,
When the denominator is two decimal places, the numerator and denominator are multiplied by 100,
When the denominator is three decimal places, the numerator and denominator are multiplied by 1000,
.

How to do if the denominator of the equation is a decimal? One is two decimal places, and the other is one decimal place. How to calculate?
0.3x-1/0.02-4x-8/0.5=1

1/0.02=50
1/0.5=2
So 50 (0.3x-1) - 2 (4x-8) = 1
15x-50-8x+16=1
7x=35
x=5

Solve the equation 6x = - 2 (x-4), remove the brackets, get (), transfer the term, merge the similar term, get (), and change the coefficient to 1, get ()

I haven't seen this question before. I suggest you ask the teacher

2004 (5x + 8) - 2005 (2x + 8) = - 5x-8, remove brackets, move items, merge similar items, and change coefficient to 1

2004(5x+8)-2005(2x+8)=-5x-82004(5x+8)-2005(2x+8)=-(5x+8)2004(5x+8)-2005(2x+8)+(5x+8)=02004(5x+8)-2005(2x+8)+1(5x+8)=0(2004+1)(5x+8)-2005(2x+8)=02005(5x+8)-2005(2x+8)=02005(5x+8-2x-8)=02005*3x=06015x=0...

1. Remove denominator 2, remove bracket 3, move item 4, merge similar item 5, coefficient to 1
1. 5 / 12 × - 4 / 4 × = 1 / 3
2. 2 / 3-8 × = 1 / 3-2 ×
3、0.5×-0.7=6.5-1.3×
4. 1 / 6 (3 × - 6) = 2 / 5 × - 3
5、3（×-7）+5（×-4）=15
6、4×-3（20-3）=-4
7. Y-1 of 2 = y + 2 of 2-5
8. 1 / 3 (1-2 ×) = 2 / 7 (3 × + 1)

1. 5 / 12 × - 4 / 4 × = 1 / 3
Remove the denominator 5x-3x = 4
Merge congeners 2x = 4
The coefficient is 1: x = 2
2. (2-8 ×) = 1 × (3-2)
De denominator 4 (2-8x) = 18-3x
Remove brackets 8-32x = 18-3x
Transfer - 32x + 3x = 18-8
Merge congeners - 29x = 10
The coefficient is 1: x = - 10 / 29
3、0.5×-0.7=6.5-1.3×
Shift 0.5x + 1.3x = 6.5 + 0.7
8 x = 7. 2
The coefficient is reduced to 1: x = 4
4. 1 / 6 (3 × - 6) = 2 / 5 × - 3
To denominator 5 (3x-6) = 12x-90
Remove bracket 15x-30 = 12x-90
Move item 15x-12x = - 90 + 30
Merge similar items 3x = - 60
The coefficient is 1: x = - 20
5、3（×-7）+5（×-4）=15
Remove bracket 3x-21 + 5x-24 = 15
Transfer 3x + 5x = 15 + 21 + 24
Merge congeners 8x = 60
The coefficient is 1: x = 7.5
6、4×-3（20-3x）=-4
Remove brackets 4x-60 + 9x = - 4
Shift 4x + 9x = - 4 + 60
Merge congeners 13X = 56
The coefficient is 1: x = 60 / 13
7. 2 (Y-1) = 2-5 (y + 2)
De denominator 5 (Y-1) = 10-2 (y + 2)
Remove bracket 5y-5 = 10-2y-4
Shift 5Y + 2Y = 10-4 + 5
Merge congeners 7Y = 11
The coefficient is 1: y = 11 / 7
8. 1 / 3 (1-2 ×) = 2 / 7 (3 × + 1)
De denominator 7 (1-2x) = 6 (3x + 1)
Remove bracket 7-14x = 18x + 6
Transfer - 14x-18x = 6-7
Merge congeners - 32x = - 1
The coefficient is 1: x = 1 / 32

Use the steps of removing brackets, moving items, merging similar items, and converting coefficient to 1 to do - 2 (X-2) = 12
﹣2（x-2）=12

Remove brackets: - 2x + 4 = 12
Transfer: - 2x = 12-4
Merge congeners: - 2x = 8
The coefficient is reduced to 1: x = - 4

When the equation 3x-2 = 1 is solved, the terms are shifted and combined to obtain, and the coefficient is changed to 1 to obtain

When the equation 3x-2 = 1 is solved, 3x = 2 + 1 is obtained by shifting the term, 3x = 3 is obtained by merging the term, and x = 1 is obtained by changing the coefficient to 1

Sina + cosa = m, then (Sina) ^ 4 + (COSA) ^ 4 =?

sina+cosa=m
Then: the square is: 2sinacosa = M & # 178; - 1
2sin²acos²a=(m^4-2m²+1)/2
(sina)^4+(cosa)^4=（sin²a+cos²a）²-2sin²acos²a=1-(m^4-2m²+1)/2==(1-m^4+2m²)/2

The process of solving the system of equations y = 2x-3 3x-2y = 5