The proposition "any x ∈ (0,3), 2x ^ - 3ax + 9"

The proposition "any x ∈ (0,3), 2x ^ - 3ax + 9"

Well organized
a>(2x^2+9)/3X
The maximum value of the right expression is 2 root sign 2
So a

It is known that the proposition p: "any x ∈ [1,2], x2-a ≥ 0", and the proposition q: "there exists x ∈ R, X2 + 2aX + 2-A = 0". If the proposition "P and Q" is true
We know the proposition p: "any x ∈ [1,2], x-a ≥ 0", and the proposition q: "there exists x ∈ R, x + 2aX + 2-A = 0". If the proposition "P and Q" is true, then the value range of real number a is obtained

If the proposition "P and Q" is true, then:
Proposition p: "any x ∈ [1,2], x-a ≥ 0 holds, a ≤ 1
Proposition q: "there exists x ∈ R, x + 2aX + 2-A = 0", there is: 1 + 2A ≠ 0, that is, a ≠ - 1 / 2
So the proposition "P and Q" is true, and the value range of real number a is a ≤ 1 and a ≠ - 1 / 2

Given proposition p: there is an X belonging to R, where x + 2aX + A is less than or equal to 0. If proposition p is a false proposition, find the value range of A
The value range of a in x ^ 2 + 2aX + A0
Why is the value range of a in truth proposition

Solution
When x ^ 2 + 2aX + A1
The above formula does not hold
When a < 1
0＜a＜1
The value range of a in true proposition is 0 < a < 1