Given that the symmetric point of M (- 5,2m-1) with respect to the origin is in the first quadrant, then the value range of M is? Answer,

Given that the symmetric point of M (- 5,2m-1) with respect to the origin is in the first quadrant, then the value range of M is? Answer,

Origin of Symmetry
So the coordinates of the symmetrical point (1-2m, 5)
Because the symmetry point is in the first quadrant
So 1-2m > 0
M < 1 / 2

Given that the point a (- 1, m) is symmetric to the origin in the first quadrant, what is the range of M?

Given that the point a (- 1, m) is symmetric with respect to the origin is (1, - M)
And it's in the first quadrant, so
-m>0
m

If the symmetric point m ′ of point m (2m + 1,3-m) about y axis is in the second quadrant, then the value range of M is___ ．

The symmetric point m ′ of ∵ point m (2m + 1, 3-m) about y axis is in the second quadrant, the ∵ point m (2m + 1, 3-m) must be in the first quadrant, ∵ 2m + 1 > 03-m > 0, the solution is: - 12 < m < 3