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In the plane rectangular coordinate system, let the point of P (2m-3,3-m) symmetric about y axis be in the second quadrant, and try to determine the value of integer M
So point P in the first quadrant is greater than 0,
If point a (2m-6,3m-1) is the point of the second quadrant and M is an integer, then the value of M is
It can be seen from the question: 2m-60; 1 / 3 solution
If point a (m-1,2m + 4) is on the bisector of the second and fourth quadrant, then M=________
Because point a (m-1,2m + 4) is on the bisector of the second and fourth quadrant
So abscissa and ordinate are opposite to each other
I have to,
(m-1)+(2m+4)=0,
The solution is m = - 1
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