Given that the distance between the point M representing the number a and the point n representing the number - 1 on the number axis is 3, and the distance between the point n representing the number B and the point n representing the number 2 is 4, calculate the distance Mn

Given that the distance between the point M representing the number a and the point n representing the number - 1 on the number axis is 3, and the distance between the point n representing the number B and the point n representing the number 2 is 4, calculate the distance Mn

I don't understand. Can we use numerical method to help us understand?

There are two points m and N on the number axis, the distance between the two points is 2011, and M is on the left side of N. after the number axis is folded, the points m and N coincide, so how many are m and N
There are two points m and N on the number axis. The distance between the two points is 2011. M is on the left side of N. after the number axis is folded, the points m and N coincide. How many points m and N are

M—1005.5,0 N 1005.5,0

It is known that a and B represent a and B respectively on the number axis. (1) according to the number axis, fill in the following table: a 6 - 6 - 6 - 62 - 1.5 B 404 - 4 - 10 - 1.5 the distance between two points a and B & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; (2) if the distance between two points a and B is D, what is the quantitative relationship between D and a and B?

(1) From the properties of absolute value, | - 6-4 | = 2; | - 6-0 | = 6; | - 6-4 | = 10; | - 6 - (- 4) | = 2; | - 2 - (- 10) | = 12; | - 1.5 - (- 1.5) | = 0

Set M = {(x, y) | XY > 0, x + y

If XY > 0, X and y have the same sign
And because of X + y

If the line X-Y + M = 0 is tangent to the square of circle x + y-2x ~ 1 = 0, then the value of M is

（x-1）²+y²=2;
Radius of center (1,0) = √ 2;
Distance from center of circle to straight line d = | 1 + m | / √ (1 + 1) = √ 2
|1+m|=2;
∴m+1=±2;
m=-1±2;
M = - 3 or M = 1;
I'm very glad to answer your questions. Skyhunter 002 will answer your questions
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Given the set P = {(x, y) iy = 2x ^ 2 + 4x + 7, - 2 less than or equal to x, less than or equal to 5}. Q = {(x, y) IX = a, y belongs to R}, then the number of elements in P intersection Q is

y=2x^2+4x+7
-2

The line y = KX + 3 and the circle (X-2) ^ 2 + (Y-3) ^ 2 = 4 intersect at two points Mn, | Mn | = 2 ″ 3

MN≦2√3
Let the distance between the center of the circle (2,3) and the straight line be d
MN²=4(r²-d²)
So, 4 (R & # 178; - D & # 178;) ≤ 12
That is: 4-D & # 178; ≤ 3
Also d

Let a = {(x, y) | y ^ 2 = x + 1} B = {(x, y) | 2Y = 4x ^ 2 + 2x + 5}, C = {(x, y) | y = KX + 6} ask whether there is a positive integer such that (a and b) intersects C = empty set
Prove your conclusion

Let me tell you how to solve the problem. Draw the graph of these three functions, and you will know that such a positive integer k does not exist, because a and C always intersect. Of course, this is a proof problem, and you can't just draw a graph to explain it
The proof can be made by using the counter proof method: assuming that there is no solution (that is, there is no solution for these equations) and then combining the two equations a, C, a and B respectively, the result is that these two equations have solutions, which is contradictory to the assumption, so

The chord length of the straight line y = KX + 6 cut by the circle x ^ 2 + y ^ 2 = 25 is 8. What formula should be used to solve the real number k?

If the center of a circle is (0,0), and the radius is r = 5, then the distance from the circle to the chord d = √ (R ^ 2-h ^ 2) = √ [5 ^ 2 - (8 / 2) ^ 2] = 3, which involves the distance formula from the point to the straight line, that is, the distance formula from the center of the circle to the straight line y = KX + 6kx-y + 6 = 0d = | k * 0-0 + 6 | / √ (k ^ 2 + 1) = 3 | 6 | = 3 √ (k ^ 2 + 1) 2 = √ (k ^ 2 + 1) k ^ 2 + 1 = 4K ^ 2 = 3K

The solution set of equations 2x + 3Y = 13,3x-2y = 0 can be expressed as___ .
I don't think it's tight,
Why can't the order of X and y be reversed? If it's conventional, how can I express my own letters, such as Q + I = 3, U + q = 5, I + U = 10

I think your question is very good! The solution of the system of equations 2x + 3Y = 13,3x-2y = 0 can actually be regarded as the problem of finding the intersection of two straight lines. The intersection is a point in the coordinate system, which is expressed by the coordinates, so the positions of X and Y in the writing method must not be interchangeable. Of course, this is not strictly written in the title, I still agree with