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What's the parity of sine function and cosine function? I don't understand!
Sine in a right triangle, the ratio of the opposite side of an acute angle to the upper hypotenuse is called the sine value of the acute angle. Sine function: when the acute angle mentioned above is a variable, its sine value changes constantly with the change of the degree of the acute angle. Take the angle as an independent variable, and its sine value as the value of the strain
1. Given the function y = asinwx + K, the maximum value of a > 0 is 4, the minimum value is 0, and the minimum positive period is Pai / 2, the analytic expression of the function is obtained
2. Known function y = sin2x-2 (SiNx + cosx) + A ^ 2
1) Find the minimum value of function y
2) If the minimum value of function y is 1, find a
If we know that a > 0 and the maximum value is 4, we can get a + k = 4 and the minimum value is 0, we can get K-a = 0 solution, a = 2, k = 2 and T = π / 2, we can know that w = 2 π / T = 4, so f (x) = 2sin4x + 2 y = sin2x-2 (SiNx + cosx) + A ^ 2, y = 2sinxcosx-2 (SiNx + cosx) + A ^ 2, let SiNx + cosx = t then
Judging the parity of function
Determine the parity of the following functions
（1）.f(x)=x^2-9
（2）.f(x)=x+1/x
(1)
f(-x)=(-x)^2-9 = x^2-9=f(x)
So it's an even function
(2)
f(-x)=-x-1/x=-(x+1/x)=-f(x)
So it's an odd function
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