Y = (LNX) x power Use the derivative of logarithm to find the derivative of the following function

Y = (LNX) x power Use the derivative of logarithm to find the derivative of the following function


y=(lnx)^x
lny=(lnx)^2
y'/y=2lnx(lnx)'=2(lnx)/x
y'=2[(lnx)^(x+1)]/x



1. If the line y = KX (K ≠ 0) bisects the second and fourth quadrants, then K ()
2. There is a point P on the function y = (1, - radical 3) X. if the abscissa of point P is 1, then the distance from P to X axis is ()
3. Given that the positive scale function passes through point a (2, - 4), point P is on the positive scale function image, B (0,4) and s △ ABP = 8, the coordinates of point P are obtained
4. If the abscissa of a point on the positive scale function y = - 2x is 4, then the distance from the point to the X axis is ()
5. If the image with positive scale function y = KX (K ≠ 0) passes through the second and fourth quadrants and P (K + 2,2k + 1), then K ()
6. If the point (- 1,2) is on the image of function y = MX + N and x-m of y = n at the same time, then the analytic expression of the positive proportion function over (m, n) is ()
7. Given that the abscissa of a point P on the image of a positive scale function is 2, take the PD ⊥ X axis (o is the origin of the coordinate, D is the perpendicular foot), and the area of △ OPD is 6. Find the analytical formula of the positive scale function
8. It is known that y is in direct proportion to X. if y decreases with the increase of X, its image is solved by a (3, - a) and B (a, - 1)
9. Given a (- 3,0) B (0,6), the area of △ AOB is divided into two parts of 1:2 by the straight line passing through the origin, and the analytical formula of the straight line is obtained


1. If the line y = KX (K ≠ 0) bisects the second and fourth quadrant angles, then K (- 1) 2. There is a point P on the function y = (1, - radical 3) X. if the abscissa of point P is 1, then the distance from P to X axis is (radical 3) 3



If AB + C = Ba + C = Ca + B = k, then the line y = KX + 2K must pass ()
A. Quadrant 1 and 2 b. quadrant 2 and 3 C. quadrant 3 and 4 d. quadrant 1 and 4


When a + B + C ≠ 0, according to the proportional property of the proportion, we get: k = a + B + C2 (a + B + C) = 12, then the straight line is y = 12x + 1, and the straight line must pass through quadrants 1, 2 and 3. When a + B + C = 0, that is, a + B = - C, then k = - 1, then the straight line is y = - X-2, that is, the straight line must pass through quadrants 2, 3 and 4