On the knowledge of linear function, inverse proportion function and quadratic function It includes the knowledge points that y increases with the increase of X and the quadrant of the function image,

On the knowledge of linear function, inverse proportion function and quadratic function It includes the knowledge points that y increases with the increase of X and the quadrant of the function image,

First order function 1. Definition: a function like y = KX + B (k, B is a constant and K is not equal to 0) is called a first order function. 2. Y = KX (k is a constant and K is not equal to 0) is a positive proportional function. 3. When K is greater than 0, y increases with the increase of X. when k is greater than 0 and B is greater than 0, the image passes through the first, second and third quadrants; when k is greater than 0 and B is less than 0

Even function, logarithmic function
1. Given that the function f (x) is an even function with a period of 2, and if x ∈ (0,1), f (x) = 2 ^ 2-1, then the value of F [(㏒ 2) 12]? {2 is the base}
2. In order to get the image of function y = [(㏒ 2) x + 3 / 1000], we only need to change all the points on the image of function y = [(㏒ 2) x]? {2 is the base}

When x ∈ (0,1), f (x) = 2 ^ 2-1
Should be f (x) = 2 ^ X - 1?
Because when x ∈ (0,1), f (x) = 2 ^ X-1
And even function of function
So when x ∈ (- 1,0), f (x) = 2 ^ (- x) - 1
Because the function has a period of 2
So the function image of the function in (1,2) is to shift the image of X ∈ (- 1,0) two units to the right
That is, change x into X-2 (left plus right minus)
So x ∈ (1,2) f (x) = 2 ^ [- (X-2)] - 1 = 2 ^ (- x + 2) - 1
Because (㏒ 2) 12 = 2 + (㏒ 2) 3
therefore
f[(㏒2)12]
=f((㏒2)3)
(㏒ 2) 3 is between (1,2)
therefore
simple form
= 2^[-((㏒2)3)+2] -1
=2^[(㏒2)(4/3)] -1
=4/3 -1
=1/3
two
Left plus right minus bottom plus minus
So it should be a
Move 3 units to the left and 3 units up
first
Translate 3 units of length to the left
Function becomes
y=（㏒10）(x+3)
then
Move up 3 units
y=（㏒10）(x+3) - 3
=（㏒10）(x+3) - (log10)1000
= (log10)[(x+3)/1000]