If point a (a + 1, b-2) is in the second quadrant, then simplify √ (a + 1) &# 178; - √ (B + 5) &# 178;

If point a (a + 1, b-2) is in the second quadrant, then simplify √ (a + 1) &# 178; - √ (B + 5) &# 178;

Given (a + 1) 0; then (B + 5) > 0, then √ (a + 1) &# 178; - √ (B + 5) &# 178; = - (a + 1) - (B + 5) = - a-1-b-5 = - (a + b) - 6

Simplification √ (√ 5 - √ 7) & # 178;

√(√5-√7)²
=√(√7-√5)²
=√7-√5

Sn = 2 / 2 + 3 / 2 & # 178; + 4 / 2 & # 179; + ··· + (n + 1) / (2 ^ n) for Sn

Sn=2/2+3/2²+4/2³+····… +n/2^(n-1)+(n+1)/(2^n) 2Sn=2+3/2+4/2²+5/2³+…… +(n + 1) / 2 ^ (n-1) down minus up to get Sn = 2 + [(1 / 2) + (1 / 4) + (1 / 8) + +[1/2^(n-1)]]-(n+1)/2^n=2+{1/2[1-(1/2)^(n-1)]/(1-1/2)}-(...