If (1 + 2x) ^ 5 = A0 + a1x + a2x ^ 2 + a3x ^ 3 + a4x ^ 4 + a5x ^ 5, then A0 + A1 + a3 + A5 = how many processes

If (1 + 2x) ^ 5 = A0 + a1x + a2x ^ 2 + a3x ^ 3 + a4x ^ 4 + a5x ^ 5, then A0 + A1 + a3 + A5 = how many processes

Substitute x = 1 to get
a0+a1+a2+a3+a4+a5=3^5=243
Substitute x = - 1 to get
a0-a1+a2-a3+a4-a5=-1
If you subtract two from one, you will get
2a1+2a3+2a5=244
a1+a3+a5=122
From the (1 + 2x) ^ 5 expansion, the constant term is 1, so A0 = 1
So A0 + A1 + a3 + A5 = 123

Fill in the blanks: (A & # 178; b) &# 178; △ a=_______ ; (- 12s ^ 4T ^ 6) / (1 / 2 S & # 178; T & # 179;) &# 178=_________ .

(A & # 178; b) &# 178; △ a = A & # 179; B & # 178;; (- 12s ^ 4T ^ 6) / (1 / 2 S & # 178; T & # 179;) &# 178; = - 48

It is specified that a kind of operation △ satisfies the following conditions: a △ B = a &# 178; - B &# 179; find the value of (- 5) △ 2

This should be a set of formulas. The result is the square of - 5 minus the cube of - 2 = 25 - (- 8) = 33

(a + b) &# 178; + | B-2 | = 0, find the value of a & # 178; - B & # 179

(a+b)²+|b-2|=0
a+b=0,b-2=0
b=2,a=-2
a²-b³
=4-8
=-4