m2-mn-2n2-m+5n-2 M2 where 2 is the square and 2n2 is the square

m2-mn-2n2-m+5n-2 M2 where 2 is the square and 2n2 is the square

m2-mn-2n2-m+5n-2
=(m-2n)(m+n)+[-(2m-4n)+(m+n]-2
=(m-2n)(m+n)-2(m-2n)+(m+n-2)
=(m-2n)(m+n-2)+(m+n-2)
=(m+n-2)(m-2n+1)

Decomposition factor: 2m2-4mn + 2n2=______ ．

The original formula is 2 (m2-2mn + N2) = 2 (m-n) 2

Factorization of (4mn-2n) / (2m-1)

(4mn-2n)/(2m-1)=2n(2m-1)/(2m-1)=2n

3/4÷[（2/3-1/6）×9]

3/4÷[（2/3-1/6）×9]
=3/4÷[（1/2×9]
=3/4×2/9
=1/6

If 1 = 4,2 = 6,3 = 9, then 4 =?

If you have a sharp brain turn, 4 = 1

Factorization of X & # 178; - Y & # 178; - Z & # 178; - 2xyz

x^2y-y^2z+z^2x-x^2z+y^2x+z^2y-2xyz
=y(x^2-2xz+z^2)+(y^2x-y^2z)-(x^2x-z^2z)
=y(x-z)^2+y^2(x-z)-xz(x-z)
=(x-z)(xy-yz+y^2-xz)
=(x-z)[x(y-z)+y(y-z)]
=(x-z)(y-z)(x+y)

The factorization result of polynomial x2y-y2z + z2x-x2z + y2x + z2y-2xyz is ()
A. （y-z）（x+y）（x-z）B. （y-z）（x-y）（x+z）C. （y+z）（x-y）（x+z）D. （y+z）（x+y）（x-z）

X2y-y2z + z2x-x2z + y2x + z2y-2xyz = (Y-Z) x2 + (z2 + y2-2yz) x + z2y-y2z = (Y-Z) x2 + (Y-Z) 2x YZ (Y-Z) = (Y-Z) [x2 + (Y-Z) x-yz] = (Y-Z) (x + y) (x-z)

1 / 12 + (4 and 12 / 5 - 3 and 1 / 2) / 11 / 24 off formula calculation

1 / 12 + (4 / 12-3 / 2) / 11 / 24
=1/12+11/12÷11/24
=1/12+2
=2 and 1 / 12
If you don't understand this question, you can ask,

Calculation: 1 / 3-1 / 2 + 1 / 4-1 / 3 + 1 / 4-1 / 2=______________

A quarter

1 / 3-1 / 2 + 1 / 4-1 / 3 + 1 / 5-1 / 4 +... + 1 / 10-1 / 9

Original form
=1/2-1/3+1/3-1/4+1/4-1/5+...+1/9-1/10
=1/2-1/10
=2/5